Brent Arias
Brent Arias

Reputation: 30165

Why does ofstream require a flush?

If I run the following code, no file is created at all:

std::ofstream outputFile(strOutputLocation.c_str(), std::ios::binary);
outputFile.write((const char*)lpResLock, dwSizeRes);
outputFile.close();

However, if I add a flush() before the close, it works:

std::ofstream outputFile(strOutputLocation.c_str(), std::ios::binary);
outputFile.write((const char*)lpResLock, dwSizeRes);
outputFile.flush();
outputFile.close();

Does the standard library actually require this, or is it a bug in the Visual C++ CRT?

Upvotes: 8

Views: 8863

Answers (2)

GManNickG
GManNickG

Reputation: 503855

It's a bug. Reading §27.8.1.10/4, abridged:

void close();
Effects: Calls rdbuf()->close()...

What does rdbuf()->close() do? According to §27.8.1.3/6, abridged, emphasis mine:

basic_filebuf<charT,traits>* close();
If is_open() == false, returns a null pointer. If a put area exists, calls overflow(EOF) to flush characters. ...

That is, it's suppose to flush. (Indeed, the call to flush() ultimately does the same thing.)


Note the call to close() itself isn't needed, as the destructor of basic_ofstream will call close().

Upvotes: 9

jbp
jbp

Reputation: 1621

Are you checking the file before you exit from the program? OS will buffer all IO, so may not see any data(unless you flush) in the file before you exit.

Upvotes: 0

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