CODEWITHSUNDEEP
iosswiftxcode
Muhammad Jamaal
Muhammad Jamaal

Reputation: 41

AES 128 Encryption for a String and generating Binary return in Swift

I have a string of data that I want to encrypt in AES 128 and the encrypted data should be in binary. I have tried using CryptoSwith to do so. But the issue I am getting is that the encryption code that I found from an online help converts in into HexString. I tried looking for the conversion to binary but couldn't find a working solution. The code I am using is below :

func encrypt(data: String) -> String?  {
        if let aes = try? AES(key: "0101010101010101", iv: "0000000000000000"),
            let encrypted = try? aes.encrypt(Array(data.utf8)) {
            return encrypted.toHexString()
        }
        return 
    }

Would really appreciate the help.

Upvotes: 1

Views: 795

Answers (1)

Dejan Skledar
Dejan Skledar

Reputation: 11435

Assuming you meant something like this?:

let binary = encrypted.map {
    let binary = String($0, radix: 2)
    let padding = String(repeating: "0", count: 8 - binary.count)
    return padding + binary
}.joined()

Which prints the whole Byte array as a sequence of zeros (0) and ones (1):

100101010101011010101010101010100011010101010101

Your method would then look like:

func encrypt(data: String) -> String?  {
    if let aes = try? AES(key: "0101010101010101", iv: "0000000000000000"),
        let encrypted = try? aes.encrypt(Array(data.utf8)) {

        let binary = encrypted.map {
            let binary = String($0, radix: 2)
            let padding = String(repeating: "0", count: 8 - binary.count)
            return padding + binary
        }.joined()

        return binary
    }
    return nil
}

Upvotes: 1

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