Reputation: 1283
i want to run a sed command with programatically with changing parameters. the thing is that i cant find the correct syntax to do so. i want to configure a conf file with this and change a dir path to another.
i'm currently using:
RESULT=$("sed 's/--ROOT_DIR--/${root_inst_dir}/g' ${root_inst_dir}/${tool_name}/etc/${tool_name}.conf > ${SOURCE_DIR}/${tool_name}.conf")
and i get the error message:
./change_tst.sh: line 7: sed 's/--ROOT_DIR--//home/test_dir/g' /home/tst/conf.conf > /home/script_tst/conf.conf: No such file or directory
the ">" is not working for some reason.
what am i doing wrong? or what is the best way to do this ?
UPDATE
i drooped the result variable and now running this:
(sed 's/--ROOT_DIR--/$root_inst_dir/g' ${root_inst_dir}/${tool_name}/etc/${tool_name}.conf) > ${SOURCE_DIR}/${tool_name}.conf
the new file is being created in > ${SOURCE_DIR}/${tool_name}.conf, but the search/replace is happening literally and not as a variable...
thanks.
Upvotes: 0
Views: 241
Reputation: 141698
Putting "
inside parenthesis will result in bash wanting to execute a command named exactly:
sed 's/--ROOT_DIR--/${root_inst_dir}/g' ${root_inst_dir}/${tool_name}/etc/${tool_name}.conf > ${SOURCE_DIR}/${tool_name}.conf"
Such command does not exist on your system.
Probably you intended to put "
outside $(...)
:
RESULT="$(sed 's/--ROOT_DIR--/${root_inst_dir}/g' ${root_inst_dir}/${tool_name}/etc/${tool_name}.conf > ${SOURCE_DIR}/${tool_name}.conf)"
Better way, if you don't need the RESULT variable and if you want to properly escape root_inst_dir
variable:
sed 's#--ROOT_DIR--#'"${root_inst_dir}"'#g' "${root_inst_dir}/${tool_name}/etc/${tool_name}.conf" > "${SOURCE_DIR}/${tool_name}.conf"
Or if you need RESULT variable:
sed 's#--ROOT_DIR--#'"${root_inst_dir}"'#g' "${root_inst_dir}/${tool_name}/etc/${tool_name}.conf" > "${SOURCE_DIR}/${tool_name}.conf"
RESULT=$(cat ${SOURCE_DIR}/${tool_name}.conf)
Upvotes: 3