CODEWITHSUNDEEP
swiftgenerics
Bhargav
Bhargav

Reputation: 713

argument type 'T.Type' does not conform to expected type 'Comparable'

I am trying to create a small class in swift but getting the following error argument type T.Type does not conform to expected type Comparable

Can someone help?

struct BST<T: Comparable> {
  let root: Node<T>?
  var count = 0

  init<T:Comparable>(data: T) {
    self.root = Node(data  : T) //Error Occurs in this line
  }
}//end class BST

Here is code of Node class.

class Node<T: Comparable> {
  let data: T
  var left: Node?
  var right: Node?

  init(data: T) {
    self.data = data
  } //end init

} //end class node

func == <T> (lhs: Node<T>, rhs: Node<T>) -> Bool {
  return lhs.data == rhs.data
} //end ==

func < <T> (lhs: Node<T>, rhs: Node<T>) -> Bool {
  if(rhs.data > lhs.data) {
    return true
  }
  return false
} //end fun <

Upvotes: 2

Views: 2552

Answers (2)

Avi
Avi

Reputation: 7552

self.root = Node(data  : T) //Error Occurs in this line

You are trying to initialize a Node with the type, instead of the value.

Try

self.root = Node(data  : data)

Upvotes: 2

Mukesh
Mukesh

Reputation: 2902

You need to pass data in the initializer not T. and also there is no need to make initialize generic.

Change your code:

struct BST<T: Comparable> {
    let root: Node<T>?
    var count = 0

    init(data: T) {
        self.root = Node(data: data)
    }

}//end class BST

Upvotes: 5

Related Questions