CODEWITHSUNDEEP
c#oauth-2.0linkedin-api
Ajai
Ajai

Reputation: 11

LinkedIn access token api returns bad request error in c#

I am using linked oauth 2 api to fetch the access token.But I am getting a 400 (BadRequest) response from that api.I am sharing the code below

NameValueCollection parameters = new NameValueCollection();
parameters.Add("grant_type", "authorization_code");
parameters.Add("code", Code);
parameters.Add("redirect_uri", RedirectURL);
parameters.Add("client_id", ClientId);
parameters.Add("client_secret", ClientSecret);


WebClient client = new WebClient();
client.Headers[HttpRequestHeader.ContentType]="application/x-www-form-urlencoded";
var result = client.UploadValues("https://www.linkedin.com/oauth/v2/accessToken", parameters);

Could anyone help me to find what went wrong here. I am passing the correct values for all parameters, got client_id, client_secret from my application and the code I am getting from my initial authorization request.

I am not able to test this scenario in postman since the auth-token request depends on the code generated from the authorization step.

Upvotes: 0

Views: 2342

Answers (1)

varun setia
varun setia

Reputation: 148

AuthorizationUrl must look like this

https://www.linkedin.com/uas/oauth2/authorization?response_type=code&client_id=78y4rii84jcf43&state=E30980C1T666444z&redirect_uri=https://www.testWeb.com

Access Token Url will look like this,

https://www.linkedin.com/uas/oauth2/accessToken?grant_type=authorization_code&code=AQTTP5DZ68JHRVO2_i9vpie8KBZ3gfgffhjfhjfhjfp88hf3szNauFkUpuvqfyKhjsmO7Bcps4JXUo1EWQay1q1q1MXKsajRWoZ4q-ofmTjJfknaYTk5SO5oHUgfhgfdsgfdgdfdgfsgdgdhgdhgddipkfTIzdkGUSWZkPYS1&client_id=78y4rii465rv084&redirect_uri=https://www.testweb.com&client_secret=1t56E7bLDl2fnVWh

And your Params are missing with

QUESTION_MARK (?) after https://www.linkedin.com/oauth/v2/accessToken

your Grant type param must include grant_type=authorization_code than & param than client_id=YourApiKey than & param than redirect_uri=YourRedirectUri than & than client_secret=YourSecretKey

Upvotes: 1

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