Reputation: 2040
Currently, I am working on c++ project I want to know how I can send an instance of a child class to function use parent as a parameter and execute a function in a child here is an example: I want Child print function to be called
Parent.h
#ifndef UNTITLED_PARENT_H
#define UNTITLED_PARENT_H
class Parent {
public:
virtual void printData();
};
#endif
Parent.cpp
#include "Parent.h"
#include <iostream>
using namespace std;
void Parent::printData() {
cout<<"Parent"<<endl;
}
Child.h
#ifndef UNTITLED_CHILD_H
#define UNTITLED_CHILD_H
#include "Parent.h"
class Child : public Parent{
public:
void printData();
};
#endif
Child.cpp
#include "Child.h"
#include <iostream>
using namespace std;
void Child::printData() {
cout<<"Child"<<endl;
}
ParentUser.h
#ifndef UNTITLED_PARENTUSER_H
#define UNTITLED_PARENTUSER_H
#include "Parent.h"
class ParentUser {
public:
void printer(Parent p);
};
#endif
ParentUser.cpp
#include "ParentUser.h"
void ParentUser::printer(Parent p) {
p.printData();
}
main.cpp
#include <iostream>
#include "Parent.h"
#include "Child.h"
#include "ParentUser.h"
int main() {
Child child;
ParentUser parentUser;
parentUser.printer(child);
return 0;
}
Upvotes: 1
Views: 165
Reputation: 8598
Your function void printer(Parent p);
will create a new object of type Parent
using a copy constructor your compiler automagically creates for you. You need to change it to take a reference instead:
void printer(Parent& p);
This will make sure that p
is actually a reference to child
, not a new Parent
created from child
using a copy constructor.
What's happening here is also called object slicing, as the copy is a parent type, which does not have any of the members defined in the child class.
Upvotes: 2