CODEWITHSUNDEEP
pythonpython-3.xdatedatetime-format
SIM
SIM

Reputation: 22440

Trouble producing list of dates in a customized manner

I've written a script to produce list of dates. The script I've tried with can do it. However, the way I need the list of dates is very different from what I'm getting at this moment.

The script I've tried with:

import datetime

start = datetime.datetime(2017,1,1)
end = datetime.datetime(2017,6,20)
daterange = [start + datetime.timedelta(days=x) for x in range(0, (end-start).days)]
for idate in daterange:
    print(idate)

Current results are like:

2017-01-01 00:00:00
2017-01-02 00:00:00
2017-01-03 00:00:00
2017-01-04 00:00:00
2017-01-05 00:00:00
2017-01-06 00:00:00

The way I expect to get the dates like:

01-01-2017 
01-02-2017  
01-03-2017  
01-04-2017  
01-05-2017  
01-06-2017

How can I modify my script to achieve the same? Thanks in advance.

Upvotes: 0

Views: 23

Answers (1)

niraj
niraj

Reputation: 18208

You can try using strftime in print, for more details you can look into documentation:

print(idate.strftime("%d-%m-%Y"))

From documentation:

%d : Day of the month as a zero-padded decimal number.

%m : Month as a zero-padded decimal number.

%Y: Year with century as a decimal number.

For testing the code above:

import datetime

start = datetime.datetime(2017,1,1)
end = datetime.datetime(2017,6,20)
daterange = [start + datetime.timedelta(days=x) for x in range(0, (end-start).days)]
for idate in daterange:
    print(idate.strftime("%d-%m-%Y"))

Result:

01-01-2017
02-01-2017
03-01-2017
04-01-2017
05-01-2017
06-01-2017
07-01-2017
08-01-2017
09-01-2017
.
.
.

Upvotes: 1

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