Reputation: 75
i have a predicate schedule(A,B,C) that returns possible permutations at lists A,B,C with backtracking
?- schedule(A,B,C).
A = [im204,212,217]
B = [im209,214,218]
C = [im210,216] ? ;
A = [im204,212,218]
B = [im209,214,217]
C = [im210,216] ? ;
A = [im204,212,216]
B = [im209,214,218]
C = [im210,217] ?
I also have the predicate schedule_errors(A,B,C,E) which returns errors (dont mind what the erros are) from lists A,B,C to E.
?- schedule_errors([im204, im209, im210], [im212, im214, im217], [im216, im218]).
E = 4 ?
In my new predicate
schedule_all_errors(A,B,C,E):-
schedule(A,B,C),
schedule_errors(A,B,C,E).
it returns possible permutations along with the error number
?- schedule_all_errors(A,B,C,E).
A = [im204,212,217]
B = [im209,214,218]
C = [im210,216]
E = 14 ? ;
A = [im204,212,218]
B = [im209,214,217]
C = [im210,216]
E = 6 ? ;
A = [im204,212,216]
B = [im209,214,218]
C = [im210,217]
E = 12 ?
I was wondering if there was a way i can return only the permutations with zero errors. (or not return any permutations whose errors are different than 0)
Upvotes: 1
Views: 139
Reputation: 170805
Just add this condition in the end
schedule_all_errors_1(A,B,C):-
schedule(A,B,C),
schedule_errors(A,B,C,E),
E = 0.
or
schedule_all_errors_1(A,B,C):-
schedule(A,B,C),
schedule_errors(A,B,C,0).
Whether the second one will work depends on the definition of schedule_errors
.
Upvotes: 2