CODEWITHSUNDEEP
swiftswift3
RSP
RSP

Reputation: 55

Split array objects into array groups in swift 3

I have an array like below:

let totalArr = ["First","Second","Third","Fourth","First","Second", "Second"]

My Required output is:

let grouper = [["First","First"],["Second", "Second", "Second"],["Third"],  ["Fourth"]]

can anybody give optimal iterations?

Upvotes: 1

Views: 1890

Answers (3)

Abhay Singh
Abhay Singh

Reputation: 265

try this :)

You can pass any String array to the function and it will return your desired result:

func groupArr(totalArr: [String]) -> [Any]{
    var grouperArr = [[String]]()
    for i in totalArr{
        let arr = totalArr.filter({($0 == i)}) as [String]
        if(grouperArr.contains(arr) == false){
            grouperArr.append(arr)
        }
    }
    return grouperArr
}

Upvotes: 3

Abdelahad Darwish
Abdelahad Darwish

Reputation: 6067

 let totalArr = ["First","Second","Third","Fourth","First","Second", "Second"]

 let grouper =   (Dictionary(grouping: totalArr, by: { $0})).map {  $0.value}

 print(grouper)

or

  let arranged =   (Dictionary(grouping: totalArr, by: { $0})).values
 print(arranged)

Upvotes: 6

Malleswari
Malleswari

Reputation: 427

You can use Dictionay's grouping function to make a group and then get all values.

let totalArr = ["First","Second","Third","Fourth","First","Second", "Second"]

let group = Dictionary(grouping: totalArr) { (object) -> String in
    let lowerBound = String.Index(encodedOffset: 0)
    let upperBound = String.Index(encodedOffset: 1)
    return String(object[lowerBound...upperBound])
}
print("group :\(group.values)")

Upvotes: 3

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