CODEWITHSUNDEEP
javaspringspring-mvcspring-annotations
tech_questions
tech_questions

Reputation: 273

Spring bean reference not working

I have the following bean:

  package com.test;
  @Component
  public class Sample{

      String modified = null;

      @Value("${url}")
      private String url;

      public Sample(){
       System.out.println(url );
        if(baseUrl.equals(""){
            throw new RuntimeException("missing");
         }
        else{
           modified = "test"+url;
        }
      }
    }

I have added: 

<context:annotation-config />
    <context:property-placeholder location="classpath:test.properties"/> &    <context:component-scan base-package="com.test"/>

and trying to access above "modified" field as below

  <bean id="url" class="java.lang.String">
        <constructor-arg value="#{sample.modified}" />
    </bean>

in my application context. But I keep getting the following error:

Field or property 'sample' cannot be found on object of type 'org.springframework.beans.factory.config.BeanExpressionContext'

Not sure why i get this error?

Upvotes: 1

Views: 624

Answers (2)

H&#233;ctor Valls
H&#233;ctor Valls

Reputation: 26084

JustinKSU's answer is right. You have another option: inject value via constructor using @Autowired:

@Component
public class Sample {

  @Autowired
  public Sample(@Value("${url}") String url) {
    System.out.println(url);
    if(url.equals("") {
      throw new RuntimeException("missing");
    }
  }

}

Upvotes: 0

JustinKSU
JustinKSU

Reputation: 4999

When Spring creates the object it uses the default constructor. It can't set the property until after it constructs it. Instead of what you have, try this to see if the value is being set.

  @PostConstruct
  public void init(){
   System.out.println(url );
    if(baseUrl.equals(""){
        throw new RuntimeException("missing");
     }
  }

Upvotes: 2

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