CODEWITHSUNDEEP
pythondjangopython-2.7django-1.11
Nurzhan Nogerbek
Nurzhan Nogerbek

Reputation: 5236

How to send file to response in Django?

I have such php function which I try to rewrite in my Django project. What should be an analogue in python for php methods like header() and show_error()? Also how to send file to response?

php:

function waprfile($date=false) {
    if(!isset($date) || $date==false) $date = date("d.m.y");

    $timestmp = date2timestamp($date);

    $filepath = "https://www.example.com/files/".$this->lang_code."/";

    if(file_get_contents($filepath.date("dmy",$timestmp).".xls"))
    {
        header("Location: ".$filepath."wapr".date("dmy",$timestmp).".xls");
    }
    else
    {
        show_error(_langWrite("No file for specified date", "Файл на указанную дату отсутствует"));
    }
}

python:

import urllib.request
import datatime
import time
from django.utils import translation

def isset(variable):
    return variable in locals() or variable in globals()

def waprfile(request, date):
    if(not isset(date) or date==False):
        date = datetime.datetime.now().strftime('%d.%m.%Y')

    timestmp = time.mktime(datatime.datetime.strptime(date, "%d.%m.%Y").timetuple())

    filepath = "https://www.example.com/files/" + str(translation.get_language()) + "/"

    formatted_date = datetime.datetime.fromtimestamp(timestmp).strftime('%d%m%y')

    if(urllib.request.urlopen(filepath + formatted_date + '.xls')):
        # What must be here?
    else:
        # What must be here?

    response = HttpResponse(content_type='application/ms-excel')
    response['Content-Disposition'] = 'attachment; filename=' + fileName
    return response

Upvotes: 15

Views: 45071

Answers (5)

Prason Ghimire
Prason Ghimire

Reputation: 529

from django.http import FileResponse
def download_file():
  return FileResponse(open('/path/to/file','rb'),
                        filename=file_name,
                        as_attachment=True,
                        content_type='application/vnd.openxmlformats-officedocument.spreadsheetml.sheet',
                        status=status,
                        )

Note: content-type should be set as per what type of file you are trying to send. the value set here is for excel type of file

Upvotes: 2

nurettin
nurettin

Reputation: 11736

Django has a FileResponse class that accepts an IO object in its constructor. So in your view:

buffer = BytesIO(excel.blob)
response = FileResponse(buffer, as_attachment=True, filename=excel.name)
response["Content-Type"] = "application/vnd.ms-excel"
return response

Upvotes: 0

mustafa candan
mustafa candan

Reputation: 836

If you want to return an image don't forget to format it as png or jpeg and return the bytes with getvalue()

img = "Suppose I am a pil image"
fomatted_img = BytesIO()
img.save(fomatted_img, format="png")
response = HttpResponse(fomatted_img.getvalue(),content_type='image/png')
response['Content-Disposition'] = 'attachment; filename="output.png"'
return response

Or you can save the formatted image directly into the response

img = "Suppose I am a pil image"
response = HttpResponse(content_type='image/png')
response['Content-Disposition'] = 'attachment; filename="output.png"'
img.save(response,"PNG")
return response

Upvotes: 1

Anurag Rana
Anurag Rana

Reputation: 1466

To return a PDF file in response in Django, use below code.

def index(request):
    data = dict()
    data["name"] = "https://www.pythoncircle.Com"
    data["DOB"] = "Jan 10, 2015"

    template = get_template('testapp/test.html')
    html = template.render(data)
    pdf = pdfkit.from_string(html, False)

    filename = "sample_pdf.pdf"

    response = HttpResponse(pdf, content_type='application/pdf')
    response['Content-Disposition'] = 'attachment; filename="' + filename + '"'
    return response

[1] https://www.pythoncircle.com/post/470/generating-and-returning-pdf-as-response-in-django/

Upvotes: 3

Satendra
Satendra

Reputation: 6865

Read file first and then send it in response.

from django.http import HttpResponse, HttpResponseNotFound

def waprfile(request, date):
    ...

    file_location = '/path/to/file/foo.xls'

    try:    
        with open(file_location, 'r') as f:
           file_data = f.read()

        # sending response 
        response = HttpResponse(file_data, content_type='application/vnd.ms-excel')
        response['Content-Disposition'] = 'attachment; filename="foo.xls"'

    except IOError:
        # handle file not exist case here
        response = HttpResponseNotFound('<h1>File not exist</h1>')

    return response

Read docs for more info: telling browser to treat the response as a file attachment and returning errors

Upvotes: 26

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