Reputation: 87
I found out, that for example this line has a very very long execution time:
System.out.println(
".. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .... .. .."
.matches("(?i)(?:.* )?\\W?([a-z0-9-_\\.]+((?: *)\\.(?: *))+(?:DE))(?:[0-9]{1,5})?")
);
If I reduce the amount of dots at the start of the String the execution time gets lower (seems like it's exponential). Here is the suspended thread's stack trace:
[Repeating text]...
Pattern$GroupTail.match(Matcher, int, CharSequence) line: 4717
Pattern$Curly.match0(Matcher, int, int, CharSequence) line: 4279
Pattern$Curly.match(Matcher, int, CharSequence) line: 4234
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$Loop.match(Matcher, int, CharSequence) line: 4785
Pattern$GroupTail.match(Matcher, int, CharSequence) line: 4717
Pattern$GroupTail.match(Matcher, int, CharSequence) line: 4717
Pattern$Curly.match0(Matcher, int, int, CharSequence) line: 4279
Pattern$Curly.match(Matcher, int, CharSequence) line: 4234
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$Single(Pattern$BmpCharProperty).match(Matcher, int, CharSequence) line: 3798
Pattern$GroupTail.match(Matcher, int, CharSequence) line: 4717
Pattern$Curly.match0(Matcher, int, int, CharSequence) line: 4272
Pattern$Curly.match(Matcher, int, CharSequence) line: 4234
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$Loop.match(Matcher, int, CharSequence) line: 4785
Pattern$GroupTail.match(Matcher, int, CharSequence) line: 4717
Pattern$GroupTail.match(Matcher, int, CharSequence) line: 4717
Pattern$Curly.match0(Matcher, int, int, CharSequence) line: 4272
Pattern$Curly.match(Matcher, int, CharSequence) line: 4234
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$Single(Pattern$BmpCharProperty).match(Matcher, int, CharSequence) line: 3798
Pattern$GroupTail.match(Matcher, int, CharSequence) line: 4717
Pattern$Curly.match0(Matcher, int, int, CharSequence) line: 4279
Pattern$Curly.match(Matcher, int, CharSequence) line: 4234
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$Loop.matchInit(Matcher, int, CharSequence) line: 4801
Pattern$Prolog.match(Matcher, int, CharSequence) line: 4741
Pattern$Curly.match0(Matcher, int, int, CharSequence) line: 4272
Pattern$Curly.match(Matcher, int, CharSequence) line: 4234
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$Ques.match(Matcher, int, CharSequence) line: 4182
Pattern$BranchConn.match(Matcher, int, CharSequence) line: 4568
Pattern$GroupTail.match(Matcher, int, CharSequence) line: 4717
Pattern$Single(Pattern$BmpCharProperty).match(Matcher, int, CharSequence) line: 3798
Pattern$Curly.match0(Matcher, int, int, CharSequence) line: 4272
Pattern$Curly.match(Matcher, int, CharSequence) line: 4234
Pattern$GroupHead.match(Matcher, int, CharSequence) line: 4658
Pattern$Branch.match(Matcher, int, CharSequence) line: 4604
Matcher.match(int, int) line: 1270
Matcher.matches() line: 604
Pattern.matches(String, CharSequence) line: 1135
String.matches(String) line: 2121
Main.main(String[]) line: 11
Why does this happen?
Upvotes: 6
Views: 1074
Reputation: 48761
When pattern x
is made optional - using ?
or *
quantifiers (or {0,}
) - engine has two paths to approach according to the nature of quantifier being used:
.*
, .?
).*?
)Someone probably is not aware about regular expressions or doesn't care about performance and throws .*
wherever he needs a match somewhere in string and engines are so fast in taking steps back and forth that nothing seems weird or slow unless a pattern can not be found.
Time complexity starts at O(n)
and continues with O(n^2b)
where b
is level of nesting quantifiers. So on failure number of steps an engine takes is HUGE.
To avoid such situations someone needs to consider some guiding principles:
Specifying boundaries. If pattern should stop somewhere before digits do not do .*
. Instead do \D*
.
Use conditions. You can check if pattern / letter x
exists before running a whole match using a lookahead ^(?=[^x]*x)
. This leads to an early failure.
Use possessive quantifiers or atomic groups (if available). These two avoid backtracks. Sometimes you do not need backtracks.
Do not do (.*)+
or similar patterns. Instead reconsider your requirements or at least use atomic groups (?>.*)+
.
Your own Regular Expression isn't an exception. It suffers from much greediness and optional matches and needs a time to be restudied.
Upvotes: 4