CODEWITHSUNDEEP
javascriptecmascript-6named-parametersdefault-parameters
Norfeldt
Norfeldt

Reputation: 9638

JavaScript (ES6): Named parameters and default values

I am coming from Python and am really liking the way to set named parameters and default values—now it seems that ES6 allows me to do similar. But I can't see why this last call breaks:

fun = ({first=1, last=1}) => (1*first+2*last)

console.log("-----------")

console.log( fun({first:1, last:2}) )

console.log("-----------")

console.log( fun({last:1, first:2}) )

console.log("-----------")

console.log( fun() ) // Breaks

Upvotes: 8

Views: 15907

Answers (2)

Jonas Wilms
Jonas Wilms

Reputation: 138234

Cause you need an object which can be deconstructed:

fun({})

Upvotes: 3

Nina Scholz
Nina Scholz

Reputation: 386512

You need a default object.

var fun = ({ first = 1, last = 1 } = {}) => 1 * first + 2 * last;
//                                 ^^^^

console.log(fun({ first: 1, last: 2 }));
console.log(fun({ last: 1, first: 2 }));
console.log(fun());

Upvotes: 35

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