Reputation: 61
I have a string called str = "12345-5, 12345-4, 12345-3, 12345-2, 12345-1
I need to reverse the string so it looks like this str = "12345-1, 12345-2, 12345-3, 12345-4, 12345-5"
I have tried the strReverse method, and it almost did what I wanted...
Sub rev()
Dim str As String
str = "12345-5, 12345-4, 12345-3, 12345-2, 12345-1"
str = StrReverse(Trim(str))
'turns out to be str = "1-54321 ,2-54321 ,3-54321 ,4-54321 ,5-54321"
End Sub
but it ended up reversing the whole string, should have guessed that. So I'm wondering should I use a regex expression to parse the string and remove the "12345-" and then reverse it and add it back in? I'm not too sure if that would be the best method for my problem. Does anyone know a solution to my problem or could point me in the right direction? Thanks
Upvotes: 1
Views: 738
Reputation: 152605
Use Split
then loop backwards through the array:
Sub rev()
Dim str As String
str = "12345-5, 12345-4, 12345-3, 12345-2, 12345-1"
Dim strArr() As String
strArr = Split(str, ",")
str = ""
Dim i As Long
For i = UBound(strArr) To LBound(strArr) Step -1
str = str & ", " & Trim(strArr(i))
Next i
str = Mid(str, 3)
Debug.Print str
End Sub
Upvotes: 6
Reputation: 43593
I would do it like this:
Sub TestMe()
Dim str As String
str = "12345-5, 12345-4, 12345-3, 12345-2, 12345-1"
str = StrReverse(str)
Dim myArr As Variant
myArr = Split(str, ",")
Dim newString As String
Dim myA As Variant
For Each myA In myArr
newString = newString & StrReverse(myA) & ","
Next myA
newString = Trim(Left(newString, Len(newString) - 1))
Debug.Print newString
End Sub
Getting this:
12345-1, 12345-2, 12345-3, 12345-4,12345-5
In general, this is quite popular Algorithmic problem, which used to be asked by Google for Junior Developers. Sounding like this - Efficiently reverse the order of the words (not characters) in an array of characters
Upvotes: 0