Reputation: 113
I am trying to make a cut out of a pipe and I want to make a curved surface to represent the outside of the pipe. However when I plot the surface I only get the diagonal of the surface instead of the surface itself. How can I fix this?
MWE:
r = 0:0.1:3;
z = 0:0.1:10;
[rr, zz] = meshgrid(r,z);
% set cut planes angles
theta1 = 0;
theta2 = pi*135/180;
nt = 101; % angle resolution
figure(1);
clf;
t3 = linspace(theta1, (theta2 - 2*pi), nt);
[rr3, tt3] = meshgrid(r,t3);
% Create curved surface
xx5 = r(end) * cos(tt3);
yy5 = r(end) * sin(tt3);
h5 = surface(xx5, yy5,zz)
Upvotes: 1
Views: 328
Reputation: 22314
The mesh-grid you created is based on theta and the radius. However, the radius is constant for the outside of the pipe so instead it should be based on theta and z since those are the two independent variables defining the grid. Based on this reasoning I believe the following is what you're after.
r = 0:0.1:3;
z = 0:0.1:10;
% set cut planes angles
theta1 = 0;
theta2 = pi*135/180;
nt = 101; % angle resolution
figure(1);
clf;
% create a grid over theta and z
t3 = linspace(theta1, (theta2 - 2*pi), nt);
[tt3, zz3] = meshgrid(t3, z);
% convert from cylindical to Cartesian coordinates
xx5 = r(end) * cos(tt3);
yy5 = r(end) * sin(tt3);
% plot surface
h5 = surface(xx5, yy5, zz3, 'EdgeColor', 'none');
% extra stuff to make plot prettier
axis vis3d
axis equal
view(3)
camzoom(0.7);
Upvotes: 2
Reputation: 861
Try with surf
with surf(xx5, yy5, zz)
. Is this what you are looking for?
Upvotes: 0