Reputation: 47
I'm trying to run multiple UNIX commands in a python script like this
import subprocess
cmds = ['sleep 3', 'uptime','time ls -l /']
p = subprocess.Popen(cmds,stdout=subprocess.PIPE,shell=True)
while p.poll() is None:
time.sleep(0.5)
tempdata = p.stdout.read()
print(tempdata)
However my output does not contain all output and doesn't seem to run all the commands. Setting shell=False also causes an error.
Traceback (most recent call last):
File "task1.py", line 32, in ?
p = subprocess.Popen(commands,stdout=subprocess.PIPE,stderr=subprocess.PIPE,shell=False)
File "/usr/lib64/python36/subprocess.py", line 550, in __init__
errread, errwrite)
File "/usr/lib64/python36/subprocess.py", line 996, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
Upvotes: 3
Views: 4424
Reputation: 19352
To run all for these:
cmds = ['sleep 3', 'uptime','time ls -l /']
You have to call popen for each of them:
for cmd in cmds:
p = subprocess.Popen(cmd, stdout=subprocess.PIPE, shell=True)
while p.poll() is None:
time.sleep(0.5)
output = p.stdout.read()
Or simpler:
for cmd in cmds:
output = subprocess.check_output(cmd, stdout=subprocess.PIPE, shell=True)
Second question: This captures all output written to stdout. To capture also stderr, redirect that into subprocess.PIPE
as well.
Upvotes: 1
Reputation: 1190
Your problem is 'sleep 3' causes the error you get from the traceback, when I removed that it worked.
Upvotes: 1
Reputation: 42421
When you create a new process, you don't pass it a list of commands to run; rather, you pass it a single command -- either as a string (with shell=True
) or as a list of args (with shell=False
).
import subprocess
cmds = ['sleep 1', 'uptime', 'ls -l /']
for cmd in cmds:
stdout = subprocess.check_output(cmd, shell=True)
print('\n# {}'.format(cmd))
print(stdout)
If you just want to collect stdout, subprocess.check_output()
might be simpler than Popen()
-- but either approach will work, depending on what you need to do with the process.
Upvotes: 3