CODEWITHSUNDEEP
python-3.xnetwork-programming
Sam Murphy
Sam Murphy

Reputation: 915

test internet connection for python3

How do I check if a python3 module is connected to the internet?

I saw this is solution for Python2 and wanted to do something similar.

Upvotes: 1

Views: 9856

Answers (5)

Frank Wallace
Frank Wallace

Reputation: 7

response = urlopen('https://www.google.com/', timeout=10)
print(response)
<http.client.HTTPResponse object at 0x0000024E196C9CC0>

so..

import sys
from urllib.request import urlopen

response = urlopen('https://www.google.com/', timeout=10)

if response == "<http.client.HTTPResponse object at 0x0000024E196C9CC0>":
    print("Ok!")
else:
    print("NO!!!")

Upvotes: -1

Soum Axetuirk
Soum Axetuirk

Reputation: 1

this is for python3 . I am using this for a while now.

import socket,time
mem1 = 0
while True:
    try:
            host = socket.gethostbyname("www.google.com") #Change to personal choice of site
            s = socket.create_connection((host, 80), 2)
            s.close()
            mem2 = 1
            if (mem2 == mem1):
                pass #Add commands to be executed on every check
            else:
                mem1 = mem2
                print ("Internet is working") #Will be executed on state change

    except Exception as e:
            mem2 = 0
            if (mem2 == mem1):
                pass
            else:
                mem1 = mem2
                print ("Internet is down")
    time.sleep(10) #timeInterval for checking

Upvotes: 0

Syed Habeeb Ullah Quadri
Syed Habeeb Ullah Quadri

Reputation: 1108

We use the following code to test the internet connection. Here generate_204 will generate code 204 when the internet is connected or else give errors.

import requests

url = 'http://clients3.google.com/generate_204'

try:
    response = requests.get(url, timeout=5)
    if response.status_code == 204:
        print(response.status_code)
        response.raise_for_status()
except requests.exceptions.RequestException as err:
    print("OOps: Something Else", err)
except requests.exceptions.HTTPError as errh:
    print("Http Error:", errh)
except requests.exceptions.ConnectionError as errc:
    print("Error Connecting:", errc)
except requests.exceptions.Timeout as errt:
    print("Timeout Error:", errt)

Upvotes: 0

Isidoros Moulas
Isidoros Moulas

Reputation: 697

You can check also only the hostname if is online: (useful is the url is an API and needs a POST, instead of a GET)

def have_internet(url):
   try:
      o = urlparse(url)
      response = urlopen(o.scheme+'://'+o.netloc, timeout=5)
      return True
   except:
      print('No access to',url)
      return False

Upvotes: 0

Sam Murphy
Sam Murphy

Reputation: 915

The following snippet worked for me.

from urllib.request import urlopen

def internet_on():
   try:
        response = urlopen('https://www.google.com/', timeout=10)
        return True
    except: 
        return False

Improved error handling and/or other configurations might be required for other use cases.

Upvotes: 5

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