Reputation: 4634
I need to update my data iteratively.
But the following way I achieved is the way too time-consuming.
Can I update multiple records with an id-value
hash?
SUBST = ''.freeze
re = /<p>|<\/p>/m
(1..1000).each do |id|
choice = QuestionChoice.find id
choice.selections.gsub!(re, SUBST)
choice.save! if choice.changed?
end
Since I found out my code could be improved by using where
Like the following
QuestionChoice.where(id: (1..1000)).each do |choice|
choice.selections.gsub!(re, SUBST)
choice.save! if choice.changed?
end
But now I still need to call save!
for every record which will cost much time.
Upvotes: 0
Views: 809
Reputation: 2624
I used to face this problem and I solved it. Try to the following:
MySQL 8.0+:
QuestionChoice.where(id: 1..1000).update_all("selections = REGEXP_REPLACE(selections, '<p>|<\/p>', '')")
Others:
QuestionChoice.where(id: 1..1000).update_all("selections = REPLACE(selections, '</p>', '')")
or
QuestionChoice.where(id: 1..1000).update_all %{
selections =
CASE
WHEN selections RLIKE '<p>|<\/p>'
THEN REPLACE(selections,'<p>|<\/p>', '')
END
WHERE selections RLIKE '<p>|<\/p>'
}
IMPORTANT: Try to put a few backlashes (\
) to your regex pattern in the clause if needed.
Upvotes: 1
Reputation: 1713
You are hitting the db 1000 times sequentially to get each record separately, try to use single query to get all records you need to update:
SUBST = ''.freeze
re = /<p>|<\/p>/m
QuestionChoice.where('id <= 1000').map do |q|
q.selections.gsub!(re, SUBST)
q.save! if q.changed?
end
Upvotes: 1