CODEWITHSUNDEEP
stringbashawksedcut
Bhavik Joshi
Bhavik Joshi

Reputation: 2677

how to find the string from the line in bash?

I have string as below,

May 29 01:30:15 apps1 docker/[a:vjwdrze2e3qxrf5eck4s3yv:a][u:jack:u][5425]: 05:30:15.693 INFO  [mockAppThread:21] app.js - API Mock App Server started successfully on 0.0.0.0 with port 7001.

As an output, I want only timestamp and the error message.

May 29 01:30:15 API Mock App Server started successfully on 0.0.0.0 with port 7001.

I can get the timestamp by awk command as below.

awk '{print $1,$2,$3}'

I can get the message as below,

cut -d "-" -f2

How can I get both in a single command? Is there any simplified way to get it?

Upvotes: 1

Views: 61

Answers (3)

NeronLeVelu
NeronLeVelu

Reputation: 10039

Depend on the recurrent strucutre (keyword). A sed solution

sed 's/\(:[0-9]\{2\}\).*\(- API\)/\1 \2/' YourFile

Upvotes: 1

Allan
Allan

Reputation: 12438

You can also use perl or sed to manipulate your file:

perl -pe 's/(?<=.{16}).*(?=-)//g' file

INPUT:

$ cat file 
May 28 04:28:15 apps1 docker/[a:vjwdrze2e3qxrf5eck4s3yv:a][u:jack:u][5425]: 05:30:15.693 INFO  [mockAppThread:21] app.js - TEST MESSAGE 3 
May 29 01:30:15 apps1 docker/[a:vjwdrze2e3qxrf5eck4s3yv:a][u:jack:u][5425]: 05:30:15.693 INFO  [mockAppThread:21] app.js - API Mock App Server started successfully on 0.1.0.0 with port 7001.
May 30 11:30:15 apps1 docker/[a:vjwdrze2e3qxrf5eck4s3yv:a][u:jack:u][5425]: 05:30:15.693 INFO  [mockAppThread:21] app.js - TEST MESSAGE 2

OUPUT:

$ perl -pe 's/(?<=.{16}).*(?=-)//g' file                                                                                                                                                                                                                        
May 28 04:28:15 - TEST MESSAGE 3 
May 29 01:30:15 - API Mock App Server started successfully on 0.1.0.0 with port 7001.
May 30 11:30:15 - TEST MESSAGE 2

Explanations:

This perl command will delete the string starting at the 17th position until the reaching the -.

Upvotes: 2

RavinderSingh13
RavinderSingh13

Reputation: 133458

Following awk may help you here.

awk '{sub(/ apps1.*app\.js/,"")} 1'  Input_file

Solution 2nd:

awk -F" app.js - " '{sub(/ apps1.*/,"",$1);print $1,$2}'   Input_file

Solution 3rd: As per Subeh's suggestion in comments adding 1 more solution now too.

awk -F'apps1|app.js -' '{ print $1 $3 }' Input_file

Upvotes: 2

Related Questions