CODEWITHSUNDEEP
linuxbashshellunix
TimmyV
TimmyV

Reputation: 31

Resolve variable from config-file based on output

I have a shell script that consist of two files, one bash-file (main.sh) and one file holding all my config-variables(vars.config).

vars.config

domains=("something.com" "else.something.com")

something_com_key="key-to-something"
else_something_com_key="key-to-something else"

In my code i want to loop through the domains array and get the key for the domain.

#!/usr/bin/env sh
source ./vars.config
key="_key"
for i in ${domains[@]}; 
do
    base="$(echo $i | tr . _)" # this swaps out . to _ to match the vars
    let farmid=$base$key 
    echo $farmid
done

So when i run it i get an error message

./main.sh: line 13: let: key-to-something: syntax error: operand expected (error token is "key-to-something")

So it actually swaps it out, but i cant save it to a variable.

Upvotes: 0

Views: 225

Answers (1)

Robert Seaman
Robert Seaman

Reputation: 2592

You can expand a variable to the value of its value using ${!var_name}, for example in your code you can do:

key="_key"
for i in ${domains[@]};
do
    base="$(echo $i | tr . _)" # this swaps out . to _ to match the vars
    farmid=$base$key
    farmvalue=${!farmid}
    echo $farmvalue
done

Upvotes: 1

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