Reputation: 658
I have a large csv with the following header columns id
, type
, state
, location
, number of students
and the following values:
124, preschool, Pennsylvania, Pittsburgh, 1242
421, secondary school, Ohio, Cleveland, 1244
213, primary school, California, Los Angeles, 3213
155, secondary school, Pennsylvania, Pittsburgh, 2141
etc...
The file is not ordered and I want a new csv file that contains all the schools with the number of students above 2000.
The answers that I found were regarding to ordered csv files, or splitting them after a specific number of rows.
Upvotes: 3
Views: 8571
Reputation: 2103
In case you just want to read file and avoid any other processing, you can use regex - (assuming this is the last column, and value are positive integers) -
import re
f1 = open('Test1.txt','wb')
with open("Test.txt") as f:
for line in f:
match = re.search(r'[2-9][0-9]{3,}$', line)
if (match):
f1.write(line)
f1.close()
Same thing will be much faster if you do it on bash -
while read line; do
K='[2-9][0-9]{3,}$'
if [[ $line =~ $K ]] ; then echo $line; fi
done <Test.txt
Upvotes: 2
Reputation: 164813
Here's a solution using csv
module:
import csv
with open('fin.csv', 'r') as fin, open('fout.csv', 'w', newline='') as fout:
# define reader and writer objects
reader = csv.reader(fin, skipinitialspace=True)
writer = csv.writer(fout, delimiter=',')
# write headers
writer.writerow(next(reader))
# iterate and write rows based on condition
for i in reader:
if int(i[-1]) > 2000:
writer.writerow(i)
Result:
id,type,state,location,number of students
213,primary school,California,Los Angeles,3213
155,secondary school,Pennsylvania,Pittsburgh,2141
Upvotes: 2