Detect if value is number in MySQL

Question

Is there a way to detect if a value is a number in a MySQL query? Such as

SELECT * 
FROM myTable 
WHERE isANumber(col1) = true

Answer 1

You can use regular expression for the mor detail https://dev.mysql.com/doc/refman/8.0/en/regexp.html

I used this ^([,|.]?[0-9])+$. This is allows handle to the decimal and float number

SELECT
    *
FROM
    mytable
WHERE
    myTextField REGEXP "^([,|.]?[0-9])+$"

Answer 2

SELECT * FROM myTable
WHERE col1 REGEXP '^[+-]?[0-9]*([0-9]\\.|[0-9]|\\.[0-9])[0-9]*(e[+-]?[0-9]+)?$'

Will also match signed decimals (like -1.2, +0.2, 6., 2e9, 1.2e-10).

Test:

drop table if exists myTable;
create table myTable (col1 varchar(50));
insert into myTable (col1) 
  values ('00.00'),('+1'),('.123'),('-.23e4'),('12.e-5'),('3.5e+6'),('a'),('e6'),('+e0');

select 
  col1,
  col1 + 0 as casted,
  col1 REGEXP '^[+-]?[0-9]*([0-9]\\.|[0-9]|\\.[0-9])[0-9]*(e[+-]?[0-9]+)?$' as isNumeric
from myTable;

Result:

col1   |  casted | isNumeric
-------|---------|----------
00.00  |       0 |         1
+1     |       1 |         1
.123   |   0.123 |         1
-.23e4 |   -2300 |         1
12.e-5 | 0.00012 |         1
3.5e+6 | 3500000 |         1
a      |       0 |         0
e6     |       0 |         0
+e0    |       0 |         0

Demo

Answer 3

Returns numeric rows

I found the solution with following query and works for me:

SELECT * FROM myTable WHERE col1 > 0;

This query return rows having only greater than zero number column that col1

Returns non numeric rows

if you want to check column not numeric try this one with the trick (!col1 > 0):

SELECT * FROM myTable WHERE !col1 > 0;

Answer 4

SELECT * FROM myTable WHERE sign (col1)!=0

ofcourse sign(0) is zero, but then you could restrict you query to...

SELECT * FROM myTable WHERE sign (col1)!=0 or col1=0

UPDATE: This is not 100% reliable, because "1abc" would return sign of 1, but "ab1c" would return zero... so this could only work for text that does not begins with numbers.

Answer 5

I have found that this works quite well

if(col1/col1= 1,'number',col1) AS myInfo

Answer 6

Try Dividing /1

select if(value/1>0 or value=0,'its a number', 'its not a number') from table

Answer 7

You can use Regular Expression too... it would be like:

SELECT * FROM myTable WHERE col1 REGEXP '^[0-9]+$';

Reference: http://dev.mysql.com/doc/refman/5.1/en/regexp.html

Answer 8

use a UDF (user defined function).

CREATE FUNCTION isnumber(inputValue VARCHAR(50))
  RETURNS INT
  BEGIN
    IF (inputValue REGEXP ('^[0-9]+$'))
    THEN
      RETURN 1;
    ELSE
      RETURN 0;
    END IF;
  END;

Then when you query

select isnumber('383XXXX') 

--returns 0

select isnumber('38333434') 

--returns 1

select isnumber(mycol) mycol1, col2, colx from tablex; -- will return 1s and 0s for column mycol1

--you can enhance the function to take decimals, scientific notation , etc...

The advantage of using a UDF is that you can use it on the left or right side of your "where clause" comparison. this greatly simplifies your SQL before being sent to the database:

 SELECT * from tablex where isnumber(columnX) = isnumber('UnkownUserInput');

hope this helps.

Answer 9

you can do using CAST

  SELECT * from tbl where col1 = concat(cast(col1 as decimal), "")

Answer 10

Still missing this simple version:

SELECT * FROM myTable WHERE `col1` + 0 = `col1`

(addition should be faster as multiplication)

Or slowest version for further playing:

SELECT *, 
CASE WHEN `col1` + 0 = `col1` THEN 1 ELSE 0 END AS `IS_NUMERIC` 
FROM `myTable`
HAVING `IS_NUMERIC` = 1

Answer 11

I recommend: if your search is simple , you can use `

column*1 = column

` operator interesting :) is work and faster than on fields varchar/char

SELECT * FROM myTable WHERE column*1 = column;

ABC*1 => 0 (NOT EQU **ABC**)
AB15*A => 15 (NOT EQU **AB15**)
15AB => 15 (NOT EQU **15AB**)
15 => 15 (EQUALS TRUE **15**)

Answer 12

If your data is 'test', 'test0', 'test1111', '111test', '111'

To select all records where the data is a simple int:

SELECT * 
FROM myTable 
WHERE col1 REGEXP '^[0-9]+$';

Result: '111'

(In regex, ^ means begin, and $ means end)

To select all records where an integer or decimal number exists:

SELECT * 
FROM myTable 
WHERE col1 REGEXP '^[0-9]+\\.?[0-9]*$'; - for 123.12

Result: '111' (same as last example)

Finally, to select all records where number exists, use this:

SELECT * 
FROM myTable 
WHERE col1 REGEXP '[0-9]+';

Result: 'test0' and 'test1111' and '111test' and '111'

Answer 13

This answer is similar to Dmitry, but it will allow for decimals as well as positive and negative numbers.

select * from table where col1 REGEXP '^[[:digit:]]+$'

Answer 14

Another alternative that seems faster than REGEXP on my computer is

SELECT * FROM myTable WHERE col1*0 != col1;

This will select all rows where col1 starts with a numeric value.

Answer 15

This should work in most cases.

SELECT * FROM myTable WHERE concat('',col1 * 1) = col1

It doesn't work for non-standard numbers like

• 1e4
• 1.2e5
• 123. (trailing decimal)