CODEWITHSUNDEEP
pythonregexpython-3.xhex
CarefullyAdvanced
CarefullyAdvanced

Reputation: 467

re.sub replace hexadecimal with string

I have a file that contains hexadecimal numbers that I want to convert to strings:

'\x73\x63\x6f\x72\x65\x73': '\x4c\x6f\x72\x65\x6d\x20\x69\x70\x73\x75\x6d',
'Status', ['\x75\x70\x64\x61\x74\x65']

But when using re.sub to replace each occurrence of a hexadecimal escaped number by its ascii representation, it doesn't seem to find the hexadecimal number in the first place.
I've tried using raw strings, but it didn't change anything. I still can't replace them.

import re, binascii
with open('hex.txt', 'r') as f:
    file = f.read()
    hexList = re.findall(r"'([\\x\w+]*)'", file)

    for item in hexList:
        file = re.sub(r"('{}')".format(item), str(binascii.unhexlify(item.replace('\\x', ''))), file)
        #file = re.sub("('"+item+"')".format(item), str(binascii.unhexlify(item.replace('\\x', ''))), file)
    print(file)```

Upvotes: 0

Views: 939

Answers (1)

pulkit-singhal
pulkit-singhal

Reputation: 847

You can use the following code fragment

import re, binascii
with open('hex.txt', 'r') as f:
    file = f.read()
    hexList = re.findall(r'((?:\\x[0-9a-f][0-9a-f])+)', file)

    for item in hexList:
        file = re.sub(r"('{}')".format(item.replace('\\', '\\\\')), str(binascii.unhexlify(item.replace('\\x', ''))), file)
    print(file)

The regex used by you for finding the hex-strings is wrong because it is even finding the Status as the hex-string.

Upvotes: 2

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