CODEWITHSUNDEEP
iphonexcodeimageimageview
Magnus
Magnus

Reputation: 57

Image array Iphone

I want to change the image in an imageview at the click of a button.

Sample code:

NSMutableArray *array = [[NSMutableArray alloc]init];

[array addObject:[UIImage imageNamed:@"pic1.png"]];
[array addObject:[UIImage imageNamed:@"pic2.png"]];
[array addObject:[UIImage imageNamed:@"pic3.png"]];

NSLog(@"%i" , [array count]);

for (int i = 0; i < [array count]; i++) {
    [type setImage:[array objectAtIndex:i]];
}

When I click the button, it displays pic3 and nothing else. Can anyone point me in the right direction?

Upvotes: 0

Views: 6041

Answers (3)

Amit Singh
Amit Singh

Reputation: 8383

Use this:

- (IBAction)buttonClicked:(id)sender
{
   static int i = 0; 
   if(i == 3)
     i = 0;
   i++;
   [type setImage:[array objectAtIndex:i]];
}

Now connect this method to your button action and type to your imageView.

Upvotes: 0

Bogatyr
Bogatyr

Reputation: 19323

There is no delay in between setting images1, 2, and 3, so you only ever see 3.

Upvotes: 0

Ratinho
Ratinho

Reputation: 298

you just set the image of the imageVIew to be pic1,then pic2 and then pic3.
if you want to change the image every click on button u should init ur array in ViewDidLoad, set int index=0;
and then, in the -(IBAction) u should inc the index and set the new pic, example: 

index=(index+1)%[array count];
[type setImage:[array objectAtIndex:index]];

Upvotes: 1

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