CODEWITHSUNDEEP
javaregexstring
Kamlesh Kanazariya
Kamlesh Kanazariya

Reputation: 1259

How to get values from below string using regex in java

I am a beginner to regex.

I have below String:

Hi Welcome to my site. #binid:BIN-4 #lat:23.025243 #long:72.5980293 #nottype:assign

Output Map : Get Map which contains all key-values as below:

bindid - BIN-4 (key=bindid, value=BIN-4)

lat - 23.025243

long - 72.5980293

nottype - assign

Upvotes: 1

Views: 63

Answers (3)

Vi Matviichuk
Vi Matviichuk

Reputation: 1132

you can extend your regex in next way: 1) initial split to get pairs (as you do it now) 2) for every pair perform another split by : which will give you first element as key and second element as value

code snippet:

public class Main {
    public static void main(String[] args) {
        Map<String, String> result = new HashMap<>();
        String input = "Hi Welcome to my site. #binid:BIN-4 #lat:23.025243 #long:72.5980293 #nottype:assign";
        String systemData = input.replace("Hi Welcome to my site. ", "");
        Arrays.asList(systemData.split("#")).forEach(pair -> {
            if (!pair.isEmpty()) {
                String[] split = pair.split(":");
                result.put(split[0], split[1]);
            }
        });

        result.entrySet().forEach( pair -> System.out.println("key: " + pair.getKey() + " value: " + pair.getValue()));
    }
}

Result:

key: binid value: BIN-4

key: nottype value: assign

key: lat value: 23.025243

key: long value: 72.5980293

Upvotes: 0

Shubhendu Pramanik
Shubhendu Pramanik

Reputation: 2751

You can try below approach for this:

String s = "Hi Welcome to my site. #binid:BIN-4 #lat:23.025243 #long:72.5980293 #nottype:assign";
        String startsWithHash = s.substring(s.indexOf('#')+1);
        String arr[] = startsWithHash.split("#");
        Map<String, String> map = new HashMap<>();
        Arrays.stream(arr).forEach(element -> map.put(element.split(":")[0], element.split(":")[1]));

        System.out.println(map.toString());

O/P:

{binid=BIN-4 , nottype=assign, lat=23.025243 , long=72.5980293 }

Upvotes: 1

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626738

You may find #, capture 1+ word chars after in the first group, match :, and then capture 1+ non-whitespace chars into the second group:

String str = "Hi Welcome to my site. #binid:BIN-4 #lat:23.025243 #long:72.5980293 #nottype:assign";
Map<String, String> res = new HashMap<String, String>();
Pattern p = Pattern.compile("#(\\w+):(\\S+)");
Matcher m = p.matcher(str);
while(m.find()) {
    res.put(m.group(1),m.group(2));
    System.out.println(m.group(1) + " - " + m.group(2)); // Demo output
}

See the Java demo.

Output:

binid - BIN-4
lat - 23.025243
long - 72.5980293
nottype - assign

Pattern details:

  • # - a # symbol
  • (\\w+) - Capturing group 1: one or more word chars
  • : - a colon
  • (\\S+)- Capturing group 2: one or more non-whitespace chars

Regex demo

Upvotes: 1

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