Reputation: 33
I have written a small script in VBA which checks the value of a cell in a given range against a list. If the cell values match a value in the list it is kept, else it is deleted. I was wondering how I could make it run backward, as running it forwards creates issues. I have researched this somewhat and I have tried appending 'Step -1' to the end of the line which begins the for loop, but this doesn't work in this case.
Set Rng = Range("A9:V9")
For Each cell In Rng
If Not myList.Exists(cell.Value) Then
cell.EntireColumn.Delete
End If
Next
Upvotes: 3
Views: 272
Reputation: 43585
In this case, probably some for-loop like this one would be enough:
Option Explicit
Sub TestMe()
Dim rng As Range
Dim cnt As Long
Set rng = Range("A9:V9")
For cnt = rng.Cells.Count To 1 Step -1
Cells(rng.Row, cnt) = 23
Stop
Next
End Sub
I have put Stop
so you can see which cell is referred. Once you hit the Stop
, continue further with F5.
Upvotes: 6
Reputation: 65
Richard, you're entirely right that the "Step -1" approach would be the right solution in this case. You simply have to change the variable references around to work with the loop.
For example:
Set Rng = Range("A9:V9")
For i = rng.rows.count to 1 step -1
for j = rng.columns.count to 1 step -1
if not myList.Exists(rng.cells(i, j).value) then
rng.cells(i, j).entirecolumn.delete ' This probably won't work, but you get the idea.
end if
next j
next i
Upvotes: 0