Reputation: 3751
I need to call a function which call a macro-function to change macro-value in runtime.
This code isn't compiled:
#define MY_MACRO 32
#define SET_MY_MACRO_VAL(IS_TRUE)(MY_MACRO=(IS_TRUE)?16:U32)
In function SET_MY_MACRO_VAL
> error: lvalue required as left operand of assignment
#define SET_MY_MACRO_VAL(IS_TRUE)(MY_MACRO=(IS_TRUE)?16:U32)
^
in expansion of macro 'SET_MY_MACRO_VAL'
SET_MY_MACRO_VAL(True);
^
Upvotes: 3
Views: 7245
Reputation: 2070
Macro value are replaced BEFORE compile time by the preprocessor and do not exist at run time.
It is not a variable it is simply a way of using text for the value "32".
If you do this :
#define MY_MACRO 32
#define SET_MY_MACRO_VAL(IS_TRUE)(MY_MACRO=(IS_TRUE)?16:U32)
It will be expanded to this
#define MY_MACRO 32
#define SET_MY_MACRO_VAL(IS_TRUE)(32=(IS_TRUE)?16:U32)
What you can do is use a #define
#ifdef SET_MACRO_VAL_32
#define MY_MACRO 32
#else
#define MY_MACRO 16
#endif
Or use a conditionnal macro if you prefer
#if (IS_TRUE>0)
#define MY_MACRO 32
#else
#define MY_MACRO 16
#endif
Edit :
In C++, you shouldn't really need macro though. You can use template and / or constexpr variable for compile-time value. In C++17 you can even use constexpr if
.
Upvotes: 3