CODEWITHSUNDEEP
typescript
Jawad Farooqi
Jawad Farooqi

Reputation: 345

how to check if an array contains a specific item

The below code gives the following error on 

"[i]" in "if (i == ingredients[i])"

error:

element implicitly has an 'any' type because index expression is not of type 'number'

code:

    let ingredients = ["ham","onion","tomato"];
    let sandwichhas = function(ingredients:string[]){
        for(let i of ingredients){
            if (i == ingredients[i]){
                return true;
            }
        }
    }

    if (snd("tomato") && snd("onion")){
      console.log("Sandwich has tomatos and onions")
    }else {
       console.log("Sandwich has no tomatos and onions")
    }

And in the if statement below there's an error saying:

Argument of type '"tomato"' is not assignable to parameter of type 'string[]'.

Argument of type '"onion"' is not assignable to parameter of type 'string[]'.

What is the workaround for this?

Upvotes: 1

Views: 525

Answers (1)

Vega
Vega

Reputation: 28708

I suggest you modify your code to the following:

let ingredients = ["ham", "onion", "tomato"];
let snd = function (item) {
    for (let i = 0; i <= ingredients.length; i++) {

        if (item === ingredients[i]) {
            return true;
        }
    }
}

if (snd("tomato") && snd("onion")) {
    console.log("Sandwich has tomatos and onions")
} else {
    console.log("Sandwich has no tomatos and onions")
}

The function argument was set to ingredient, instead of a string parameter that you pass, such as "tomato" and "onion". They are of type "string", it is ingredient[], an array fro now. i in the iteration was used mistakenly also.

Upvotes: 1

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