CODEWITHSUNDEEP
c#restapidropbox
Jitesh Dammani
Jitesh Dammani

Reputation: 43

DropBox API calls Uploading a Zero byte file

I am trying to upload a file to dropbox using rest calls but it is not uploading the actual file, it is uploading a zero byte file.

Please check the code and let me know if i am missing something.

var task = Task.Run((Func<Task<int>>)OrderExtractUsecase.DropBox);
task.Wait();
int x = task.Result;

Dropbox task Code is: 

static async Task<int> DropBox()
    {
        try
        {
            Dropbox_Utility objDropBox = new Dropbox_Utility("<accessid>");
            foreach (string temp in fileList)
            {
                await objDropBox.Upload("/Assist", temp);
            }
            return 1;
        }
        catch(Exception ex)
        {
            return -1;
        }
    }

Upload task code is:

    public async Task<string> Upload(string folder, string filefullpath)
    {
         string filename = string.Empty;
         string fileID = string.Empty;
         try
         {
            filename = Path.GetFileName(filefullpath);

            using (FileStream fileStream = File.OpenRead(filefullpath))
            {
                using (MemoryStream memoryStream = new MemoryStream())
                {
                    fileStream.CopyTo(memoryStream);
                    var response = await dbx.Files.UploadAsync(folder + "/" + filename, WriteMode.Overwrite.Instance, body: memoryStream);
                    fileID = response.Id;
                }
            }
        }
        catch (Exception ex) { throw; }
        finally { }
        return fileID;
    }

Upvotes: 0

Views: 508

Answers (1)

Greg
Greg

Reputation: 16940

As awh112 mentioned, you need to reset the position of memoryStream. After the copyTo, the Position of memoryStream is the length of the file. For that reason, your code will upload a zero byte file. I've confirmed as much with the following:

fileStream.CopyTo(memoryStream);
Console.WriteLine(memoryStream.Position);
var response = await dbx.Files.UploadAsync(folder + "/" + filename, WriteMode.Overwrite.Instance, body: memoryStream);
Console.WriteLine((response as FileMetadata).Size);

That prints: (in my case, my test file is just 12 bytes long)

12
0

You can rewind it like this:

fileStream.CopyTo(memoryStream);
Console.WriteLine(memoryStream.Position);
memoryStream.Position = 0;
Console.WriteLine(memoryStream.Position);
var response = await dbx.Files.UploadAsync(folder + "/" + filename, WriteMode.Overwrite.Instance, body: memoryStream);
Console.WriteLine((response as FileMetadata).Size);

That prints:

12
0
12

The resulting uploaded file then contains the expected contents.

Upvotes: 1

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