Reputation: 73
This is my sample code:
I need it to result like this:
category outlet1 outlet2 outlet3
Sale 70 20 40
Expense 250 130 200
How can I do this?
EDIT: My outlets are not fixed, sorry for not telling this beforehand.
Upvotes: 0
Views: 53
Reputation: 24763
you may also use the PIVOT
operator
SELECT *
FROM
(
SELECT category, outletname, amt
FROM tblcategory c
INNER JOIN tbltran t ON t.catid = c.id
INNER JOIN tbloutlet o ON o.id = t.outletid
) d
PIVOT
(
SUM(amt)
FOR outletname in ([Outlet1] , [Outlet2] , [Outlet3])
) p
EDIT : below is the Dynamic SQL version
declare @Outlets nvarchar(max),
@SQL nvarchar(max)
select @Outlets = isnull(@Outlets + ',', '') + quotename(outlet)
from outlet
select @SQL = '
SELECT *
FROM
(
SELECT category, outletname, amt
FROM tblcategory c
INNER JOIN tbltran t ON t.catid = c.id
INNER JOIN tbloutlet o ON o.id = t.outletid
) d
PIVOT
(
SUM(amt)
FOR outletname in (' + @Outlets + ')
) p'
print @SQL -- print out for verification
exec sp_executesql @SQL
Upvotes: 0
Reputation: 418
Here with dynamic Outlets http://sqlfiddle.com/#!18/a7b09/25
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT ',' + QUOTENAME(outletname)
from tbloutlet
group by outletname
order by outletname
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT category,' + @cols + ' from
(
SELECT c.category, o.outletname, SUM(t.amt) as amt
FROM tblcategory c
INNER JOIN tbltran t ON t.catid = c.id
INNER JOIN tbloutlet o ON o.id = t.outletid
GROUP BY c.category, o.outletname
) x
pivot
(
sum(amt)
for outletname in (' + @cols + ')
) p '
execute(@query);
Upvotes: 1
Reputation: 1269753
You can solve your particular problem using conditional aggregation:
SELECT c.category,
SUM(CASE WHEN o.outletname = 'Outlet1' THEN t.amt ELSE 0 END) as Outlet1,
SUM(CASE WHEN o.outletname = 'Outlet2' THEN t.amt ELSE 0 END) as Outlet2,
SUM(CASE WHEN o.outletname = 'Outlet3' THEN t.amt ELSE 0 END) as Outlet3
FROM tblcategory c INNER JOIN
tbltran t
ON t.catid = c.id INNER JOIN
tbloutlet o
ON o.id = t.outletid
GROUP BY c.category;
If the outlet names are not fixed, then you need dynamic SQL. The problem cannot be solve using a single SELECT
query.
Upvotes: 1