CODEWITHSUNDEEP
pythondatetimestrptime
UCProgrammer
UCProgrammer

Reputation: 557

turn string into time

How would I get this string '201806070908' into a datetime object? Right now this is YYYYMMDDMMSS. I could get rid of Seconds (S) if needed. I was looking at strptime() but I'm not sure this could be used. It is possible to convert this? The time is part of a directory name and I am looking to upload the most recent file back to another machine.

If anyone can assist or point me in the right direction, then that would be great. Thanks

Upvotes: 0

Views: 61

Answers (2)

SkyLine
SkyLine

Reputation: 54

from datetime import datetime
x = '201806070908'
print datetime.strptime(x, '%Y%d%m%I%M%S')

Should work.

Upvotes: 0

sacuL
sacuL

Reputation: 51405

strptime should work:

import datetime

s = '201806070908'

dt = datetime.datetime.strptime(s, '%Y%m%d%M%S')

datetime.datetime(2018, 6, 7, 0, 9, 8)

You can test that this worked:

>>> dt.day
7
>>> dt.month
6
>>> dt.year
2018
>>> dt.minute
9
>>> dt.second
8

Upvotes: 3

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