CODEWITHSUNDEEP
python
Abhinav Sharma
Abhinav Sharma

Reputation: 307

Printing even characters in a string and ignoring white strings

I need something like this accepted_string: An apple a day keeps the doctor away resultant_string: Aapedyepteotrwy

And for this I have written this code:

accepted_string = input("enter")
add = ''

for count in range(0, len(accepted_string), 2):

    if accepted_string[count] == " ":
        count += 1
        add = add + accepted_string[count]
    else:
        add = add + accepted_string[count]
print(add)

But this is giving me different output while passing the above sample input. The logic is also correct, then where is the error? I have to skip to next character whenever I encounter a whitespace. Please help me as I am new to this

Upvotes: 1

Views: 62

Answers (2)

Nihal
Nihal

Reputation: 5344

you can remove space before hands instead of doing in for loop and make it list to convert in into array

Code:

accepted_string = input("enter")
add = ''
accepted_string = list(accepted_string.replace(" ", ""))
print(accepted_string)

for count in range(0, len(accepted_string), 2):
    add = add + accepted_string[count]

print(add)

output:

['A', 'n', 'a', 'p', 'p', 'l', 'e', 'a', 'd', 'a', 'y', 'k', 'e', 'e', 'p', 's', 't', 'h', 'e', 'd', 'o', 'c', 't', 'o', 'r', 'a', 'w', 'a', 'y']
Aapedyepteotrwy

2nd code:

accepted_string = input("enter")
add = ''

char_count = 1
for count in range(0, len(accepted_string)):

    if accepted_string[count] != " ":
        char_count += 1
        if char_count % 2 == 0:
            add = add + accepted_string[count]
        # add = add + accepted_string[count]
    # else:
    #     add = add + accepted_string[count]
print(add)

output:

Aapedyepteotrwy

Upvotes: 0

user2390182
user2390182

Reputation: 73480

Simple string slicing with prior replacement:

>>> s = "An apple a day keeps the doctor away"
>>> s.replace(" ", "")[::2]
'Aapedyepteotrwy'

Upvotes: 2

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