CODEWITHSUNDEEP
pythonbashlistshell
kbg
kbg

Reputation: 245

Passing a list in shell script

This is the first time I am working with shell scripts. Passing one element at a time works. However I have got confused because I have a method which requires a list as an argument and currently, whatever I tried, it just takes the first element of list. But I wish to pass the entire list at one time only.

run.sh

#!/bin/bash
list = 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5 0.55 0.6 0.65 0.7 0.75 0.8 0.85 0.9 0.95;
qsub job.sh "label" $list

job.sh

#!/bin/bash
python file.py $1 $2

file.py

import sys
import os
from myClass import myClass
label = sys.argv[1]
list = sys.argv[2]
myObject = myClass(label,list)

Upvotes: 0

Views: 2011

Answers (2)

Mark Setchell
Mark Setchell

Reputation: 207758

You need to double quote things with spaces in the shell, and drop spaces around assignments (=)

list="0.1 0.2 24 45"
qsub job.sh "label" "$list"

and

python file.py "$1" "$2"

Upvotes: 3

user590028
user590028

Reputation: 11728

Try this

job.sh

#!/bin/bash
python file.py $*

file.py

import sys
import os
from myClass import myClass
label, list = sys.argv[1], sys.argv[2:]
myObject = myClass(label, list)

Upvotes: 0

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