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Nic
Nic

Reputation: 1

populating <select> tag with PHP

I am trying to dynamically populate a select tag in php, by printing values from an array of objects.

this is my code

for($i = 0; $i < count($z); $i++)
{
    print('<option value ="'.$z[i]->getId().'">'.$z[i]->getDescription().'</option>');
}

the array is populated, in fact if i try to print only the fields i get a result, but in the combo-box nothing appears

Upvotes: 0

Views: 35

Answers (3)

Nic
Nic

Reputation: 1

ok, i resolved by creating two support arrays

$ids = array();
$descs = array();
for ($i = 0; $i < count($z); $i++) {
    $ids[$i] = $z[$i]->getId();
    $descs[$i] = $z[$i]->getDescritpion();
}

and using them instead of the objects 

for ($i = 0; $i < count($z); $i++) {
     print('<option value ="' . $ids[$i] . '">' . $descs[$i] . '</option>');
}

not very efficient, but working. thanks for the answer :)

Upvotes: 0

Shoukat Mirza
Shoukat Mirza

Reputation: 828

Add select tag and replace i with $i

echo "<select>";
for($i = 0; $i < count($z); $i++) {
    echo '<option value ="'.$z[$i]->getId().'">'.$z[$i]->getDescription().'</option>';
}
echo "</select>";

Upvotes: 0

Pradeep
Pradeep

Reputation: 9707

Replace i with $i

<select name="name">
  <?php
  for($i = 0; $i < count($z); $i++)
  {
    print('<option value ="'.$z[$i]->getId().'">'.$z[$i]->getDescription().'</option>');
  }?>
</select>

Upvotes: 1

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