CODEWITHSUNDEEP
javascriptregex
olegzhermal
olegzhermal

Reputation: 859

JS Regex for a string contains fixed number of letters

Let's say I need to have minimum 5 letters in a string not requiring that they are subsequent. The regex below checks subsequent letters

[A-Za-z]{5,}

So, "aaaaa" -- true, but "aaa1aa" -- false.

What is the regex to leave the sequence condition, that both of the strings above would pass as true.

Upvotes: 0

Views: 455

Answers (5)

Majva
Majva

Reputation: 150

w means alphanumeric in regex, it will be ok : \w{5,}

Upvotes: 1

CertainPerformance
CertainPerformance

Reputation: 371138

If you have to use a regular expression only, here's one somewhat ugly option:

const check = str => /^(.*[A-Za-z].*){5}/.test(str);
console.log(check("aaaaa"));
console.log(check("aa1aaa"));
console.log(check("aa1aa"));

Upvotes: 1

Yossi Vainshtein
Yossi Vainshtein

Reputation: 4005

Allow non-letter characters between the letters:

(?:[A-Za-z][^A-Za-z]*){5,}

Upvotes: 1

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627410

You could remove all non-letter chars with .replace(/[^A-Za-z]+/g, '') and then run the regex:

var strs = ["aaaaa", "aaa1aa"];
var val_rx = /[a-zA-Z]{5,}/;
for (var s of strs) { 
  console.log( val_rx.test(s.replace(/[^A-Za-z]+/g, '')) );
}

Else, you may also use a one step solution like

var strs = ["aaaaa", "aaa1aa"];
var val_rx = /(?:[^a-zA-Z]*[a-zA-Z]){5,}/;
for (var s of strs) { 
  console.log( s, "=>", val_rx.test(s) );
}

See this second regex demo online. (?:[^a-zA-Z]*[a-zA-Z]){5,} matches 5 or more consecutive occurrences of 0 or more non-letter chars ([^a-zA-Z]*) followed with a letter char.

Upvotes: 4

Strelok
Strelok

Reputation: 51481

[a-zA-Z0-9]{5,}

Just like this? Or do you mean it needs to be a regex that ignores digits? Because the above would match aaaa1 as well.

Upvotes: 0

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