CODEWITHSUNDEEP
phparraysloopsfor-loopcalendar
Tom Jelfs
Tom Jelfs

Reputation: 27

PHP For Loop repeating an array

I'm trying to create a calendar system that will show what jobs are booked in for certain days, I want it to be a horizontal calendar that has all of the days of the months as a table row and days of the week as the next row. I've got the first row sorted but I need to have the second row repeat the array of the days of the week until the month ends.

      //Establish How many days are in the current Month
  $currentMonthDays = date("t");




  $daysOfWeek = array('M','T','W','T','F','Sa','Su');

      echo '<table cellpadding="0" cellspacing="0" border="1" bordercolor="ffffff">
            <tr>';


                    for ($i = 1; $i <= $currentMonthDays; $i++)
                    {

                        echo '<td width="30" align="center">'.$i.'</td>';
                    }

      echo '</tr><tr>';


                    foreach($daysOfWeek as $day){
                    echo '<td width="30" align="center">'.$day.'</td>';
                    }


      echo '</tr>';

Upvotes: 1

Views: 427

Answers (3)

vogomatix
vogomatix

Reputation: 5041

The easiest way to do this to use the DateTime class and formatting methods you used to get the number of days to also format the date for you.

$currentMonthDays = date('t');
$month = date('m');
$year = date( 'Y');

for ($i = 1; $i <= $currentMonthDays; $i++) {
    echo '<td width="30" align="center">'.$i.'</td>';
}
$day = new DateTime();
for ($i = 1; $i <= $currentMonthDays; $i++) {
    $day->setDate( $year, $month, $currentMonthDays);
    // this outputs first 3 letters of day, but you can truncate if you want..
    echo '<td width="30" align="center">'.$day->format('D').'</td>';
}

You could also avoid the need for 2 loops by merging the two tds and formatting the cell by either adding a br element between the day of the month and the day of the week, or using CSS formatting.

Upvotes: 0

Salar Pourfallah
Salar Pourfallah

Reputation: 1582

Try below code

    $currentMonthDays = date("t");

    $daysOfWeek = array('M', 'T', 'W', 'T', 'F', 'Sa', 'Su');

    echo '<table cellpadding="0" cellspacing="0" border="1" bordercolor="ffffff">
        <tr>';

    for ($i = 1; $i <= $currentMonthDays; $i++) {

        if ($i % 7 == 1) 
            echo '</tr><tr>';
        echo '<td width="30" align="center">' . $i . '</td>';
    }

    echo '</tr><tr>';


    foreach ($daysOfWeek as $day) {
            echo '<td width="30" align="center">' . $day . '</td>';
    }


    echo '</tr>';

maybe helps you.

Upvotes: 0

waren0809
waren0809

Reputation: 111

Try this : 

 //Establish How many days are in the current Month
  $currentMonthDays = date("t");
  $daysOfWeek = array('M','T','W','T','F','Sa','Su');
      for ($i = 0; $i <= $currentMonthDays-1; $i++){
          $arrayWeekDays[] = $daysOfWeek[($i%7)];
      }
      echo '<table cellpadding="0" cellspacing="0" border="1" bordercolor="ffffff">
            <tr>';


                    for ($i = 1; $i <= $currentMonthDays; $i++)
                    {

                        echo '<td width="30" align="center">'.$i.'</td>';
                    }

      echo '</tr><tr>';


                    foreach($arrayWeekDays as $day){
                    echo '<td width="30" align="center">'.$day.'</td>';
                    }


      echo '</tr>';

Cheers :)

Upvotes: 1

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