CODEWITHSUNDEEP
androidbutton
Repox
Repox

Reputation: 15476

Set the Button state and keep it after onClick

I'm not sure this is even possible. I have this button:

<Button 
android:id="@+id/b1" 
android:layout_width="wrap_content" 
android:layout_height="45px"
android:drawableTop="@drawable/buttontv"
android:layout_weight="1"
android:background="@null"
android:textColor="#ffffff"
android:textSize="9px"
android:text="TV"/>

And this button has this item xml:

<?xml version="1.0" encoding="utf-8"?>
<selector
xmlns:android="http://schemas.android.com/apk/res/android">
<item
 android:state_focused="true"
 android:state_pressed="false"
 android:drawable="@drawable/tv" />
<item
 android:state_focused="true"
 android:state_pressed="true"
 android:drawable="@drawable/tv_pressed" />
<item
 android:state_focused="false"
 android:state_pressed="true"
 android:drawable="@drawable/tv_pressed" />
<item  
 android:drawable="@drawable/tv" />
</selector>

And in my application I use this code for when clicking my button:

            OnClickListener b1Listener = new OnClickListener(){             
                    @Override
                    public void onClick(View v) {   loadUrl("http://example.org/"); v.setPressed(true); }
            };
            Button b1 = (Button) findViewById(R.id.b1);
            b1.setOnClickListener(b1Listener);

What I would like that when I have pressed the button, the drawableTop sets to one of the items with the @drawable/tv_pressed attribute value - and stays there (as in 'this is the currently active button').

I tried adding v.setPressed(true) in the onClick function (as this was all I could find with Google) but that didn't work.

Can this be done? Or is there a better alternative to what I'm trying to accomplish?

Upvotes: 3

Views: 11872

Answers (4)

everyman
everyman

Reputation: 3407

https://stackoverflow.com/a/9750125/1257369

    button.setFocusable(true);
    button.setFocusableInTouchMode(true);///add this line

or with styles.xml

    <item name="android:focusable">true</item>
    <item name="android:focusableInTouchMode">true</item>

Upvotes: 1

Luis Nu&#241;ez
Luis Nu&#241;ez

Reputation: 80

Are you working with dialogs/dialogfragments? This code might help you if you are, because i had a simmilar problem and this worked for me. :)

1- extend your class with DialogFragment ,Override Onstart() method.

@Override
public void onStart() {
super.onStart();
final AlertDialog D = (AlertDialog) getDialog();
if (D != null) {
    Button positive = (Button) D.getButton(Dialog.BUTTON_POSITIVE);
    positive.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View arg0) {
            if (edittext.equals("")) {
  Toast.makeText(getActivity(), "EditText empty don't close",Toast.LENGTH_SHORT).show();
            } else {
            D.dismiss(); //dissmiss dialog
            }
        }
    });
}}

Upvotes: 0

kevinl
kevinl

Reputation: 4214

as mentioned above by the answer, it is ideal to use a togglebutton but if you are using a listview in this scenario, then the togglebutton will block out your listview's setOnItemClickListener. You can fix that issue as well by adding the descendants as blocked in the listview layout. However some people have reported that even then, their listview items won't click after using toggle buttons.

Upvotes: 0

Rich
Rich

Reputation: 36806

If you need a button that gets pressed and stays active, use a ToggleButton

Upvotes: 5

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