Reputation: 123
I am trying to make an on screen keyboard. It works for widgets in the window but when I press a button it moves focus from the window I am trying to type in to the window that has the buttons. How do I prevent python from moving?
from tkinter import *
from pynput.keyboard import Key, Controller
keyboard = Controller()
class App:
def __init__(self, master):
self.entry = Entry()
self.buttonOne = Button(text='1')
self.buttonTwo = Button(text='2')
self.buttonThree = Button(text='3')
self.buttonOne.bind("<Button-1>", lambda event, keyPressed='1': self.pressed(event, keyPressed))
self.buttonTwo.bind("<Button-1>", lambda event, keyPressed='2': self.pressed(event, keyPressed))
self.buttonThree.bind("<Button-1>", lambda event, keyPressed='3': self.pressed(event, keyPressed))
self.entry.grid(row=0, column=0, columnspan=3)
self.buttonOne.grid(row=1, column=0)
self.buttonTwo.grid(row=1, column=1)
self.buttonThree.grid(row=1, column=2)
def pressed(self, event, keyPressed):
keyboard.press(keyPressed)
keyboard.release(keyPressed)
root = Tk()
app = App(root)
root.mainloop()
Upvotes: 1
Views: 895
Reputation: 15513
Question: Keep from moving focus to window
On X11, you can set the -type
attribute:
self.wm_attributes("-type", 'dock')
'dock'
will working for me not to grab the focus, but are not supported by all window managers.
Reference:
Communicate with window manager
-type
Requests that the window should be interpreted by the window manager as being of the specified type(s). This may cause the window to be decorated in a different way or otherwise managed differently, though exactly what happens is entirely up to the window manager.
'dock'
indicates a dock/panel feature,
import tkinter as tk
class App(tk.Tk):
def __init__(self):
super().__init__()
self.wm_attributes("-type", 'dock')
for n in range(64, 68):
btn = tk.Button(self, text=chr(n), takefocus=0)
btn.bind("<Button-1>", self.on_click)
btn.pack()
def on_click(self, event):
w = event.widget
print(w['text'])
if __name__ == '__main__':
App().mainloop()
Upvotes: 1
Reputation: 142
I would suggest using withdraw()
and deiconify()
. This will make it so the window with the button is invisible once you call it on that window. Once you use deiconify()
it reverses this and makes it visible again.
More information can be found here.
Upvotes: 2