Reputation: 11
I just started with this project and tried to check whether I was going the right way. I run this code but got one "FileNotFound exception must be caught or thrown" error. What do I do now? Am I going the right way?
package com.company;
import java.util.Scanner;
import java.io.File;
public class Main
{
public static void main(String[] args)
{
Game game = new Game();
String s = game.OpenFile();
System.out.println(s);
}
}
class Game
{
public Game(){
moviename = " ";
}
private String moviename;
public String OpenFile()
{
File file = new File("movienames.txt");
Scanner ip = new Scanner(file);
int rnum = (int)(Math.random()*10)+1;
int count = 0;
while(ip.hasNextLine())
{
moviename = ip.nextLine();
count++;
if(count==rnum)
{
break;
}
}
return moviename;
}
Upvotes: 0
Views: 54
Reputation: 12819
Yes you are going in the right way. What this warning is saying is that you must handle the FileNotFound
exception. You have two options: Throw it or surround the code in a try-catch
block:
Throwing the exception:
public String OpenFile() throws FileNotFoundException
{
File file = new File("movienames.txt");
Scanner ip = new Scanner(file);
int rnum = (int)(Math.random()*10)+1;
int count = 0;
while(ip.hasNextLine())
{
moviename = ip.nextLine();
count++;
if(count==rnum)
{
break;
}
}
return moviename;
}
public String OpenFile()
{
try {
File file = new File("movienames.txt");
Scanner ip = new Scanner(file);
int rnum = (int)(Math.random()*10)+1;
int count = 0;
while(ip.hasNextLine())
{
moviename = ip.nextLine();
count++;
if(count==rnum)
{
break;
}
}
}catch(Exception e) {
e.printStackTrace();
}
return moviename;
Some good readings:
Difference between try-catch and throw in java
https://beginnersbook.com/2013/04/try-catch-in-java/
Upvotes: 1