Reputation: 515
I have a dataframe which looks like this:
I1 I2 V
0 1 1 300
1 1 5 7
2 1 9 3
3 2 2 280
4 2 3 4
5 5 1 5
6 5 5 400
I1 and I2 represent indexes while V represent values. The indexes with values equal to 0 have been omitted, but I'd like to get a confusion matrix showing all the values, i.e. something like this:
1 2 3 4 5 6 7 8 9
1 300 0 0 0 7 0 0 0 3
2 0 280 4 0 0 0 0 0 0
3 0 0 0 0 0 0 0 0 0
4 0 0 0 0 0 0 0 0 0
5 5 0 0 0 400 0 0 0 0
6 0 0 0 0 0 0 0 0 0
7 0 0 0 0 0 0 0 0 0
8 0 0 0 0 0 0 0 0 0
9 0 0 0 0 0 0 0 0 0
How can I do it?
Thanks in advance!
Upvotes: 1
Views: 470
Reputation: 77007
Option 1: Using numpy
you can
In [150]: size = df[['I1', 'I2']].values.max()
In [151]: arr = np.zeros((size, size))
In [152]: arr[df.I1-1, df.I2-1] = df.V
In [153]: idx = np.arange(1, size+1)
In [154]: pd.DataFrame(arr, index=idx, columns=idx).astype(int)
Out[154]:
1 2 3 4 5 6 7 8 9
1 300 0 0 0 7 0 0 0 3
2 0 280 4 0 0 0 0 0 0
3 0 0 0 0 0 0 0 0 0
4 0 0 0 0 0 0 0 0 0
5 5 0 0 0 400 0 0 0 0
6 0 0 0 0 0 0 0 0 0
7 0 0 0 0 0 0 0 0 0
8 0 0 0 0 0 0 0 0 0
9 0 0 0 0 0 0 0 0 0
Option 2: Using scipy.sparse.csr_matrix
In [178]: from scipy.sparse import csr_matrix
In [179]: size = df[['I1', 'I2']].values.max()
In [180]: idx = np.arange(1, size+1)
In [181]: pd.DataFrame(csr_matrix((df['V'], (df['I1']-1, df['I2']-1)), shape=(size, si
...: ze)).toarray(), index=idx, columns=idx)
Out[181]:
1 2 3 4 5 6 7 8 9
1 300 0 0 0 7 0 0 0 3
2 0 280 4 0 0 0 0 0 0
3 0 0 0 0 0 0 0 0 0
4 0 0 0 0 0 0 0 0 0
5 5 0 0 0 400 0 0 0 0
6 0 0 0 0 0 0 0 0 0
7 0 0 0 0 0 0 0 0 0
8 0 0 0 0 0 0 0 0 0
9 0 0 0 0 0 0 0 0 0
Upvotes: 2
Reputation: 863301
Use set_index
with unstack
for reshape, for append missing values add reindex
and for data cleaning rename_axis
:
r = range(1, 10)
df = (df.set_index(['I1','I2'])['V']
.unstack(fill_value=0)
.reindex(index=r, columns=r, fill_value=0)
.rename_axis(None)
.rename_axis(None, axis=1))
print (df)
1 2 3 4 5 6 7 8 9
1 300 0 0 0 7 0 0 0 3
2 0 280 4 0 0 0 0 0 0
3 0 0 0 0 0 0 0 0 0
4 0 0 0 0 0 0 0 0 0
5 5 0 0 0 400 0 0 0 0
6 0 0 0 0 0 0 0 0 0
7 0 0 0 0 0 0 0 0 0
8 0 0 0 0 0 0 0 0 0
9 0 0 0 0 0 0 0 0 0
Detail:
print (df.set_index(['I1','I2'])['V']
.unstack(fill_value=0))
I2 1 2 3 5 9
I1
1 300 0 0 7 3
2 0 280 4 0 0
5 5 0 0 400 0
Alternative solution with pivot
, if all values are integers:
r = range(1, 10)
df = (df.pivot('I1','I2', 'V')
.fillna(0)
.astype(int)
.reindex(index=r, columns=r, fill_value=0)
.rename_axis(None)
.rename_axis(None, axis=1))
print (df)
1 2 3 4 5 6 7 8 9
1 300 0 0 0 7 0 0 0 3
2 0 280 4 0 0 0 0 0 0
3 0 0 0 0 0 0 0 0 0
4 0 0 0 0 0 0 0 0 0
5 5 0 0 0 400 0 0 0 0
6 0 0 0 0 0 0 0 0 0
7 0 0 0 0 0 0 0 0 0
8 0 0 0 0 0 0 0 0 0
9 0 0 0 0 0 0 0 0 0
Upvotes: 2