CODEWITHSUNDEEP
pythonpython-3.x
Daniel Mana
Daniel Mana

Reputation: 10391

How to create an array that sums the value of a 2d array

[[2, 3, 4, 6, 9],
 [4, 6, 8, 12, 18],
 [6, 9, 12, 18, 27],
 [8, 12, 16, 24, 36],
 [10, 15, 20, 30, 45],
 [12, 18, 24, 36, 54],
 [14, 21, 28, 42, 63],
 [16, 24, 32, 48, 72],
 [18, 27, 36, 54, 81],
 [20, 30, 40, 60, 90]]

I wanted to sum to value into an array.

Basically, I have this array data, how do I get this output.

The output is something like this 

[2+3+4+6+9, 2+3+4+6+18, 2+3+4+6+27, 2+3+4+6+36, 2+3+4+6+45, 2+3+4+6+54, 2+3+4+6+63, 2+3+4+6+71, 2+3+4+6+81, 2+3+4+6+90, 4+3+4+6+9, ...]

I tried something like this and it didn't work

final = [] trans = [*zip(*data)]

k = 0 l = 0

while(k != len(trans) * len(data)):   val = 0   m = 0   for d1 in trans:
    val = val + d1[m * l]
    m = m + 1   l = l + 1   k = k + 1   final.append(val)

Upvotes: 0

Views: 68

Answers (2)

Fourier
Fourier

Reputation: 2983

In python2:

summed_array = map(sum,array)

for python3:

summed_array = list(map(sum,array))

To do what you have literally requested:

[sum(row[:-1]) + x[-1] for row in array for x in array]

Upvotes: 0

Taohidul Islam
Taohidul Islam

Reputation: 5414

Do you want this?

my_list = [[2, 3, 4, 6, 9],
 [4, 6, 8, 12, 18],
 [6, 9, 12, 18, 27],
 [8, 12, 16, 24, 36],
 [10, 15, 20, 30, 45],
 [12, 18, 24, 36, 54],
 [14, 21, 28, 42, 63],
 [16, 24, 32, 48, 72],
 [18, 27, 36, 54, 81],
 [20, 30, 40, 60, 90]]

sum_list = [sum(i) for i in my_list]
print(sum_list)

Upvotes: 1

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