CODEWITHSUNDEEP
swiftfoundationsquare-root
The Lone Coder
The Lone Coder

Reputation: 3104

How to calculate the 6th root of 2 in Swift?

I am trying to calculate the 6th root of 2 in Swift and I cannot find a suitable function in for this.

There has been one post here titled "How to find the nth root of a value?" where the proposed solution was to use 

pow(2, (1/6))

But I believe this does not work, as the signature for pow is

func pow(_ x: Decimal, _ y: Int) -> Decimal

so the result of the above formula is 1 instead of 1.122462... as (1/6) gets rounded to 0.

The iPhone calculator can do it, so there must be way :)

Thanks!

Upvotes: 1

Views: 380

Answers (1)

vacawama
vacawama

Reputation: 154613

To compute the 6th root of 2:

pow(2.0, 1.0/6.0)

You just need to use Doubles.

There are multiple versions of pow for different data types. By using the floating point literals, Swift will infer them be of type Double and select pow with this signature:

func pow(_: Double, _: Double) -> Double

Or you can use logarithms (nth root of x is exp(log(x)/n) where x and n are Doubles:

exp(log(2.0) / 6.0)

Upvotes: 5

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