CODEWITHSUNDEEP
xmlxsltxpathxslt-3.0
jbrehr
jbrehr

Reputation: 815

XSL XPATH if statement in tokenize()

I have an XML document containing lists of people structured like this:

<listPerson>
 <person xml:id="John_de_Foo">
  <persName>
     <forename>John</forename>
     <nameLink>de</nameLink>
     <surname>Foo</surname>
     <role>snake charmer</role>
  </persName>
 </person>
 <person xml:id="John_de_Foo_jr">
  <persName>
     <forename>John</forename>
     <nameLink>de</nameLink>
     <surname>Foo</surname>
     <genname>junior</genname>
  </persName>
 </person>
 <person xml:id="M_de_Foo">
  <persName>
     <forename>M</forename>
     <nameLink>de</nameLink>
     <surname>Foo</surname>
  </persName>
 </person>
 [...]
</listPerson>

I am extracting only certain fields and concatenating them with tokenize() to create a new element <fullname> using XSL 3.0 (where $doc = current document):

<xsl:template match="listPerson/person"> 
 <fullname>
   <xsl:value-of select="$p/persName/name, $p/persName/forename, $p/persName/nameLink, $p/persName/surname, $p/persName/addName, $p/persName/genName" separator=" "/>
 </fullname>
<xsl:template/>

Outputs:

<fullname>John de Foo</fullname>
<fullname>John de Foo junior</fullname>
<fullname>M de Foo</fullname>

But, I'd like to treat the element <forename> with a specific test. If the forename/@text is a single initial, add . . The new result would output:

<fullname>John de Foo</fullname>
<fullname>John de Foo junior</fullname>
<fullname>M. de Foo</fullname>

Also, the <forename> element may not exist, in which case it should bypass the test.

I can do this by changing the tokenize() to a series of <xsl:if> statements, but I'd rather try to solve it within XPATH if possible.

Thanks in advance

Upvotes: 2

Views: 327

Answers (2)

Martin Honnen
Martin Honnen

Reputation: 167401

If you want the forename to be suffixed with a full stop if it has a string length on one you can in XPath 3.1 use forename!(if (string-length() eq 1) then . || '.' else .) e.g. in a full template:

  <xsl:template match="persName">
      <fullname>
          <xsl:value-of select="forename!(if (string-length() eq 1) then . || '.' else .), nameLink, surname, genname" separator=" "/>
      </fullname>
  </xsl:template>

https://xsltfiddle.liberty-development.net/bdxtq5

Will of course work the same with a different expression e.g. $p/persName/forename!(if (string-length() eq 1) then . || '.' else .)

Upvotes: 3

zx485
zx485

Reputation: 29022

In XPath 2.0 there is an if-then-else expression which you can use directly in the xsl:value-of like this:

<xsl:value-of select="$p/persName/name, if (string-length($p/persName/forename) = 1) then concat($p/persName/forename,'.') else $p/persName/forename , $p/persName/nameLink, $p/persName/surname, $p/persName/addName, $p/persName/genName" separator=" " />

An alternative is using the if-then-else in the concat(...) function:

<xsl:value-of select="$p/persName/name, concat($p/persName/forename, if (string-length($p/persName/forename) = 1) then '.' else ''), $p/persName/nameLink, $p/persName/surname, $p/persName/addName, $p/persName/genName" separator=" " />

Upvotes: 5

Related Questions