Reputation: 17553
I want to delete the last newline present in my file using java. I mean, there is a newline at the very end of the file, which I want to remove.
I have tried many solutions provided online, but nothing works.
The below code removes all newlines from file
trimm.replace("\n", "").replace("\r", "");
Sample text:
ABC 123|1|2 ABC '123|1|2|"Jan 30 2018 2:34:13:000AM"|dd1|1|"Jan 30 2018 2:56:08:000AM"|EST' ABC 20180821
ABC 123|1|2 ABC '123|1|2|"Jan 30 2018 2:34:13:000AM"|dd1|1|"Jan 30 2018 2:56:08:000AM"|EST' ABC 20180821
The above sample has newline at the end. I have referred the URLs below:
http://www.avajava.com/tutorials/lessons/how-do-i-remove-a-newline-from-the-end-of-a-string.html
https://www.java-forums.org/new-java/22655-removing-last-blank-line-txt-file.html
I can't use split()
after \n
as many raws have same word
My code:
String actual ="ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\r\n" +
"ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\r\n";
try {
File fout = new File("I:\\demo\\S2.txt");
FileOutputStream fos = new FileOutputStream(fout);
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(fos));
String trimm= actual;
/* StringBuilder sb = new StringBuilder(trimm);
int lastEnterPosition = trimm.lastIndexOf("\r\n");
sb.replace(lastEnterPosition, lastEnterPosition + 1, "");
trimm = sb.toString();*/
trimm = trimm.replaceAll("[\n\r]+$", "");
bw.write(trimm);
bw.newLine();
bw.close();
} catch (FileNotFoundException e){
// File was not found
e.printStackTrace();
} catch (IOException e) {
// Problem when writing to the file
e.printStackTrace();
}
Any workaround will be helpful.
Upvotes: 3
Views: 4895
Reputation: 5294
If you know that the string will always end with \r\n
, given
String test = "your string that ends with a newline\r\n";
You can use something like
String eol = "\r\n";
int eolLen = eol.length();
String tmp = test.substring(0, test.length()-eolLen);
Using a regex seems a bit overkill. You could optionally check to see that the string really ends with a newline and throw an exception of some kind or another if it's possible that you get bad input. Something like:
String check = test.substring(test.length() - eolLen);
if (!eol.equals(check)) {
throw new Exception(String.format("Expected newline, found %s", check));
}
Upvotes: 1
Reputation: 59978
You can use replaceFirst
which use regex with this one [\n\r]+$
, like so :
trimm = trimm.replaceFirst("[\n\r]+$", "");
I tried this piece of code :
public static void main(String[] args) throws Exception {
String trimm = "ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\n" +
"ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\r\n";
System.out.println("---------------------------------------------------Before replace Start of the input---------------------------------------------------");
System.out.println(trimm);
System.out.println("---------------------------------------------------Before replace End of the input---------------------------------------------------");
System.out.println("---------------------------------------------------After replace Start of the input---------------------------------------------------");
trimm = trimm.replaceFirst("[\n\r]+$", "");
System.out.println(trimm);
System.out.println("---------------------------------------------------After replace End of the input---------------------------------------------------");
}
The output :
---------------------------------------------------Before replace Start of the input---------------------------------------------------
ABC 123|1|2 ABC '123|1|2|"Jan 30 2018 2:34:13:000AM"|dd1|1|"Jan 30 2018 2:56:08:000AM"|EST' ABC 20180821
ABC 123|1|2 ABC '123|1|2|"Jan 30 2018 2:34:13:000AM"|dd1|1|"Jan 30 2018 2:56:08:000AM"|EST' ABC 20180821
---------------------------------------------------Before replace End of the input---------------------------------------------------
---------------------------------------------------After replace Start of the input---------------------------------------------------
ABC 123|1|2 ABC '123|1|2|"Jan 30 2018 2:34:13:000AM"|dd1|1|"Jan 30 2018 2:56:08:000AM"|EST' ABC 20180821
ABC 123|1|2 ABC '123|1|2|"Jan 30 2018 2:34:13:000AM"|dd1|1|"Jan 30 2018 2:56:08:000AM"|EST' ABC 20180821
---------------------------------------------------After replace End of the input---------------------------------------------------
Note that there are a break line before the replace and after the replace only the last break line is removed.
I tried this three solutions :
public static void main(String[] args) throws Exception {
String trimm = "ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\n" +
"ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\r\n";
try {
File fout = new File("path");
FileOutputStream fos = new FileOutputStream(fout);
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(fos));
trimm = trimm.replaceAll("[\n\r]+$", "");
bw.write(trimm);
//bw.newLine();//<-----------------------note this
bw.close();
} catch (FileNotFoundException e) {
// File was not found
e.printStackTrace();
} catch (IOException e) {
// Problem when writing to the file
e.printStackTrace();
}
}
public static void main(String[] args) throws Exception {
String trimm = "ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\n" +
"ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\r\n";
Path path = Paths.get("path");
try (BufferedWriter writer = Files.newBufferedWriter(path))
{
writer.write(trimm.replaceFirst("[\n\r]+$", ""));
}
}
public static void main(String[] args) {
String trimm = "ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\n" +
"ABC 123|1|2 ABC '123|1|2|\"Jan 30 2018 2:34:13:000AM\"|dd1|1|\"Jan 30 2018 2:56:08:000AM\"|EST' ABC 20180821\r\n";
try {
Files.write(Paths.get("path"), trimm.replaceFirst("[\n\r]+$", "").getBytes());
} catch (IOException e) {
e.printStackTrace();
}
}
and all the three codes gives me :
Upvotes: 3