CODEWITHSUNDEEP
javascriptarraysobjectconsole.log
gwydion93
gwydion93

Reputation: 1923

Printing objects of one value based on another value

I want to console.log a value within an array of objects based on another specific value. For example, I have a simple array of objects. For all of the objects with v: 1, I want to print the z value.

  var array = [
    {v:1, z: 4},
    {v:3, z: 8},
    {v:4, z: 6},
    {v:1, z: 4},
    {v:2, z: 9},
    {v:2, z: 3},
    {v:4, z: 7},
    {v:1, z: 5},
  ];

I tried something like for (array.v(1) => { console.log(array.z); }); but the syntax isnt correct. What is the correct syntax here?

Upvotes: 0

Views: 29

Answers (2)

Gerardo BLANCO
Gerardo BLANCO

Reputation: 5648

You need to add a if statement to your for each loop

Also you can use a filter function but this will print the object that meet your filter, not only the z value

var array = [
    {v:1, z: 4},
    {v:3, z: 8},
    {v:4, z: 6},
    {v:1, z: 4},
    {v:2, z: 9},
    {v:2, z: 3},
    {v:4, z: 7},
    {v:1, z: 5},
  ];
  
 console.log('For Each')
 array.forEach(o=>{ if(o.v == 1)console.log(o.z)})
 console.log('Filter')
 console.log(JSON.stringify(array.filter(o=>o.v==1)))

Upvotes: 1

Darrin Cullop
Darrin Cullop

Reputation: 1208

Try something like this:

array.forEach( function(a) { if ( a.v == 1 ) console.log(a.z); } );

Upvotes: 2

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