CODEWITHSUNDEEP
c++hexdecimaldata-conversion
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Reputation: 664

Converting a decimal value into a hex value with the same visible representation

I am working on a microcontroller which only outputs number in a hexadecimal representation. I have data which is calculated in decimal and is meant for a human to read and interpret. My output is the three decimal numbers 45, 27, and 91, when I output these I get 0x2D, 0x1B, and 0x5B. What operation can I perform to convert 45 to 0x45, 27 to 0x27 and so on.

Upvotes: 1

Views: 1271

Answers (2)

mostawk
mostawk

Reputation: 71

Though I think it is not a good idea to convert 45 to 0x45, here is the method:

int dec = 45;
int hex = 0;
int i = 1;
while(dec/10 != 0){
    int digit = dec%10;
    hex += digit*i;
    i *=16;
}
cout << hex << endl;// if you convert "hex" to hexadecimal, it would be 0x45

Upvotes: 1

izlin
izlin

Reputation: 2138

If I understand you correctly you want something like this:

unsigned char convert(unsigned char in) {
    return ((in % 10) * 0x01) + ((in / 10) * 0x10);
}

int main()
{
    unsigned char a = 45;
    printf ("0x%02X", convert(a)); // prints "0x45"
    return 0;
}

It converts the decimal value 45 to 0x45 which is equivalent to decimal 69. Note that the convert function is not really fast on microcontrollers because of the division /.

It can only print decimal values from 0 to 99 because there are only two digits to use.

Upvotes: 2

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