Reputation: 97
Say I have a list of tables. (sym1, sym2, sym3
etc)
How would I add a new column to each table called Sym
containing the table name?
Thank you
Upvotes: 1
Views: 254
Reputation: 3229
Another way to achieve this :
q){update Sym:x from x}each `sym1`sym2`sym3
q)raze (sym1;sym2;sym3)
p s Sym
----------------
2.08725 75 sym1
2.065687 6 sym1
2.058972 63 sym2
2.095509 62 sym2
2.036151 90 sym3
2.090895 63 sym3
If you are getting these tables (sym1,sym2,sym3
) as the output of another function call like :
f each `s1`s2`s3
then I'll suggest updating the function to add the column Sym
just before return these individual tables.
f:{
/some logic
update Sym:x from t
}
This will save an operation of adding a new column separately
Upvotes: 0
Reputation: 31
You could use something like:
q){@[value x;`Sym;:;x]}each tables[]
+`a`b`c`Sym!(0 1 2 3 4;0 1 2 3 4;0 1 2 3 4;`sym1`sym1`sym1`sym1`sym1)
+`a`b`c`Sym!(0 1 2 3 4;0 1 2 3 4;0 1 2 3 4;`sym2`sym2`sym2`sym2`sym2)
+`a`b`c`Sym!(0 1 2 3 4;0 1 2 3 4;0 1 2 3 4;`sym3`sym3`sym3`sym3`sym3)
If you remove value
from the first argument of @
, this will update the tables in place.
Otherwise, since this returns a list, you can use indexing to return the table you want from the list:
q)({@[value x;`Sym;:;x]}each tables[])0
a b c Sym
----------
0 0 0 sym1
1 1 1 sym1
2 2 2 sym1
3 3 3 sym1
4 4 4 sym1
Hope this helps,
James
Upvotes: 2