Reputation: 21
I need to get the latest date where number is changed I have this SQL statement
Select
a.group, a.date a.number
From
xx.dbo.list a
Where
a.group in ('10, '10NC', '210')
And a.date >= '2018-06-01'
And a.number > 0
And a. number <> (Select Top 1 b.number
From xxx.dbo.list b
Where b.group = a.group
And b.date >= '2018-06-01'
And b.number > 0
And b.date < a.date
Order by b.date desc)
order by a.date desc
I have a table that looks like this
Group date Number
--------------------------
10 2018-02-06 4
10 2018-04-06 4
10 2018-06-12 4
10NC 2018-02-06 68
10NC 2018-04-06 35
10NC 2018-06-11 35
10NC 2018-06-12 68
10NC 2018-06-13 35
210 2018-06-02 94
210 2018-06-04 100
210 2018-06-06 100
210 2018-06-07 93
I get this output now, but I only want to get the rows with X
Group date Number
------------------------------
10NC 2018-06-12 68
10NC 2018-06-13 35 X
210 2018-06-04 100
210 2018-06-07 93 X
Can anyone help?
Upvotes: 1
Views: 159
Reputation: 16
Is this what is Expected?
DECLARE @List TABLE ([Group] VARCHAR(100), [Date] DATE, Number INT)
INSERT INTO @List
SELECT '10','2018-02-06',4
UNION ALL
SELECT '10','2018-04-06',4
UNION ALL
SELECT '10','2018-06-12',4
UNION ALL
SELECT '10NC','2018-02-06',68
UNION ALL
SELECT '10NC','2018-04-06',35
UNION ALL
SELECT '10NC','2018-06-11',35
UNION ALL
SELECT '10NC','2018-06-12',68
UNION ALL
SELECT '10NC','2018-06-13',35
UNION ALL
SELECT '210','2018-06-02',94
UNION ALL
SELECT '210','2018-06-04',100
UNION ALL
SELECT '210','2018-06-06',100
UNION ALL
SELECT '210','2018-06-07',93
;WITH CTE AS
(
SELECT
*
,RN = ROW_NUMBER() OVER (Partition by [Group] ORDER BY [DATE] DESC)
FROM @List
WHERE
[Date] >= '2018-06-01'
AND [Group] in ('10', '10NC', '210')
And Number > 0
)
SELECT * FROM CTE WHERE RN = 1
Note: I am posting it directly in answer as i don't have enough reputation to ask questions in comments.
Upvotes: 0
Reputation: 1270993
You would use lag()
:
select a.*
from (select a.group, a.date, a.number, lag(a.number) over (partition by group order by date) as prev_number
From xx.dbo.list a
where a.group in ('10', '10NC', '210') And
a.date >= '2018-06-01' And
a.number > 0
) a
where prev_number <> number;
Upvotes: 2