CODEWITHSUNDEEP
phphtml
Sky Hopper
Sky Hopper

Reputation: 1

Show button if two conditions are met

So I have a button that I want to show and hide on certain parts. So if $unlockcourse is false AND the $courseid is 1, I would like the button to be hidden, BUT I would like it to be shown at all other times no matter what the courseidis

      $courseid = ($userinfo['course']) * 1;
      $mycourse = ($userinfo['id_course']) * 1;
       $unlockcourse = true;
        if($haspaid == 1){
            $unlockcourse = false;
        } else if ($haspaid == 0) {
            $unlockcourse = true;   
        }

    <?php if ($unlockcourse == false && $mycourse >= 1) { ?> 
     <a href="course-work-proc.php" class="btn btn-primary">Resume Course</a>
      <?php } ?>

Upvotes: 0

Views: 905

Answers (3)

Victoria Ruiz
Victoria Ruiz

Reputation: 5013

So what you actually want to do is show it if unlockcourse is false, and mycourse is 1. This means that to find out when to show it, you need to negate both conditions like this: 

 <?php if (!($unlockcourse == false && $mycourse == 1)) { ?> 
     <a href="course-work-proc.php" class="btn btn-primary">Resume Course</a>
      <?php } ?>

Upvotes: 0

Esmond Gunasekara
Esmond Gunasekara

Reputation: 48

Try Editing the following code 

 <?php if ($unlockcourse == false && $mycourse >= 1) { ?> 
     <a href="course-work-proc.php" class="btn btn-primary">Resume Course</a>
      <?php } ?>

into

         <?php if !($unlockcourse == false && $mycourse >= 1){
         echo "<a href='course-work-proc.php' class='btn btn-primary'>Resume Course</a>";
}?>

This will make the button appear when your statements are true, and nothing will appear when the statement is false

Upvotes: 1

Praveen Kumar Purushothaman
Praveen Kumar Purushothaman

Reputation: 167182

I am surprised how did this not throw an error. The error lies here:

if ($unlockcourse == false) && if ($mycourse == 1) && {

It should be:

if ($unlockcourse == false && $mycourse == 1) {

Upvotes: 1

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