Reputation: 31
In my Django template I am having some problem to hyperlink. The link is a dynamically generated IP (not a file location).
in views.py
def basestations(request, host_id):
'ipaddr': basestation.mni_address
some code
return render_to_response('basestations.html', locals(), context_instance=RequestContext(request))
This variable holding the dynamically produced IP address from database and passes to front end in the variable name basestation.mni_address
In Django template, I want the basestation should be hyperlinked with the basestation.mni_address
<td><a href="{% url what should I write here? %}"><i
class="icon-th-large"></i> {{ basestation.name }}</a></td>
e.g. basestation.name is also passed to front end dynamically. This basestation.name should be hyperlinked with the IP address, means while clicking on the name, user should be forwarded to a link as ex -'http://192.168.255.66'
Any help is much appreciated.
Upvotes: 0
Views: 229
Reputation: 599956
You wouldn't use {% url %}
at all. That's for generating links to other URLs within your Django app. You want to link to an IP address, so just put that value in directly:
<a href="{{ basestation.mni_address }}">
Upvotes: 1